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BloomLocke367

  • one year ago

Help with Pre-Cal?

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  1. jdoe0001
    • one year ago
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    posting specifics helps

  2. BloomLocke367
    • one year ago
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    It says to solve algebraically and confirm graphically, and the first problem is \(v^2-5=8-2v^2\)

  3. BloomLocke367
    • one year ago
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    I was getting there, lol XD

  4. jdoe0001
    • one year ago
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    \(\bf v^2-5=8-2v^2\implies v^2+2v^2=8+5\implies v=?\)

  5. triciaal
    • one year ago
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    put the variables on one side constants on the other keep the balance of the equation

  6. BloomLocke367
    • one year ago
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    When I solved aglebraically I got \(v=\sqrt{\frac{13}{3}}\)

  7. BloomLocke367
    • one year ago
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    But when I graphed it, I don't think it's right... but I may have made an error. That's why I'm asking for help.

  8. BloomLocke367
    • one year ago
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    oops, I meant to say when I graphed it, it didn't match my algebraic solution.

  9. jdoe0001
    • one year ago
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    notice, is a quadratic equation, 2nd degree polynomial, thus 2 answers \(\bf v^2-5=8-2v^2\implies v^2+2v^2=8+5\implies v=\pm\sqrt{\cfrac{13}{3}}\)

  10. BloomLocke367
    • one year ago
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    I forgot to put that, but I know that. lol

  11. jdoe0001
    • one year ago
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    hmmm ok.... so.. whathmm how did you do the graph anyway? just a table of values?

  12. BloomLocke367
    • one year ago
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    I set the equations equal to zero

  13. BloomLocke367
    • one year ago
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    and used a calculator

  14. BloomLocke367
    • one year ago
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    equation**

  15. jdoe0001
    • one year ago
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    so.... I'd think... the graph is ok...no?

  16. BloomLocke367
    • one year ago
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    obviously, I got a parabola with the y-intercept -13. And my zeroes were \(\pm\)2.082

  17. BloomLocke367
    • one year ago
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    Is that correct?

  18. jdoe0001
    • one year ago
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    \(\bf \pm\sqrt{\cfrac{13}{3}}=\pm2.08166599946613273528\) so, the zeros look fine

  19. BloomLocke367
    • one year ago
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    ohhhh... so I was right, sorry. I was thinking of something else when I graphed it and that was my problem lol

  20. BloomLocke367
    • one year ago
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    Thanks *facepalm*

  21. triciaal
    • one year ago
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    |dw:1440630977887:dw|

  22. BloomLocke367
    • one year ago
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    Thanks!

  23. jdoe0001
    • one year ago
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    http://fooplot.com/#W3sidHlwZSI6MCwiZXEiOiIzeF4yLTEzIiwiY29sb3IiOiIjMDAwMDAwIn0seyJ0eXBlIjoxMDAwLCJ3aW5kb3ciOlsiLTguMzQ5OTk5OTk5OTk5OTk4IiwiNy45IiwiLTEzLjU1MDAwMDAwMDAwMDAwMiIsIi0zLjU0OTk5OTk5OTk5OTk5OSJdfV0- drag the graph down, to see the intercepts anyhow, you can zoom in/out by using the mouse middle-button so those are the intercepts

  24. BloomLocke367
    • one year ago
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    yeah, I have the graph right in front of me. I was just thinking I was looking for something else, I don't know why. XD

  25. jdoe0001
    • one year ago
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    In every work of genius we recognize our own rejected thoughts: they come back to us with a certain alienated majesty. ~~ Ralph Waldo Emerson ~~

  26. BloomLocke367
    • one year ago
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    Very wise. I have another one, but I think I need to use completing the square to do it.. Can you maybe help?

  27. jdoe0001
    • one year ago
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    sure, post anew, more eyes :)

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