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BloomLocke367
 one year ago
Solve algebraically and confirm graphically.
\((x+11)^2=121\)
BloomLocke367
 one year ago
Solve algebraically and confirm graphically. \((x+11)^2=121\)

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BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0I got it down to \(x^2+22x=0\)

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0and I'm pretty sure I need to complete the square, right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well... do you how to complete the square? :)

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0I did... lemme see if I can remember XD It's been almost an entire year since I've done it xp

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0and nope. I can't remember. Just tell me what to do first and I'm pretty sure I'll catch on quickly since I'm already somewhat familiar with it.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1You don't need to complete the square. Just factor out x on the left side.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmmm actually. right.. as @mathstudent55 said... you could just do common factoring

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0\(x^2+22x+121\). That's it expanded

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0but it is set equal to 121

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1\((x+11)^2=121\) \(x^2 + 22x + 121 = 121\) \(x^2 + 22x = 0\) \(x(x + 22) = 0\) Now continue.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.0Factor x out, then use the fact that if ab=0, then a=0 OR b=0.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0ohhhhhhhhhhhhhhhhh

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(x^2+22x=0\implies x(x+22)=0\implies \begin{cases} x=0\\ x+22=0 \end{cases}\)

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0so x=0 and x=22

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0Thank you for making me remember stuff that I forgot XD

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0But now I don't know who to medal >.<

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well.. @BloomLocke367 that's nonimportant anyway :)

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1The way the problem was given originally, it was already a completed square. You could have done this: \((x + 11)^2 = 121\) \(x + 11 = \pm \sqrt{121} \) \(x + 11 = \pm 11\) \(x + 11 = 11\) or \(x + 11 = 11\) \(x = 0\) or \(x = 11\)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0Why not just take the square root of both sides? \[\large (x+11)^2 = 121\] \[\large \sqrt{(x+11)^2} = \sqrt{121}\] \[\large x+11 = 11 \ ...\ \text{Rule:} \sqrt{x^2} = x \text{ where x is a real number}\] \[\large x+11 = 11 \ \text{ or } \ x+11 = 11\] \[\large x= ??\ \text{ or } \ x = ??\]

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Now you need to do it graphically.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0Wow, thank you for making me see things in many different ways. That helps a ton. Thank you all! I would give all of you a medal if I could.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.0oh my goodness these are getting more and more complex as they go on.
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