anonymous
  • anonymous
I need help, but I think I understand most of it.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
From a boat on the lake, the angle of elevation to the top of a cliff is 18°41'. If the base of the cliff is 991 feet from the boat, how high is the cliff (to the nearest foot)?
anonymous
  • anonymous
So I already know I need to use tan
jim_thompson5910
  • jim_thompson5910
you should have something like this drawn up |dw:1440632228679:dw|

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anonymous
  • anonymous
tan (h/991)
jim_thompson5910
  • jim_thompson5910
it should be tan(18°41') = h/991
jim_thompson5910
  • jim_thompson5910
tan(angle) = opp/adj |dw:1440632425483:dw|
anonymous
  • anonymous
Oh okay
anonymous
  • anonymous
Does 18'41 mean the same as 18.41?
jim_thompson5910
  • jim_thompson5910
no
jim_thompson5910
  • jim_thompson5910
the `41'` means "41 arcminutes". Sometimes the book will drop the "arc" and just say "41 minutes"
jim_thompson5910
  • jim_thompson5910
Rule: 1 degree = 60 arcminutes think of it as 60 minutes in an hour
jim_thompson5910
  • jim_thompson5910
divide both sides of `1 degree = 60 arcminutes` by 60 to get (1/60) degree = 1 arcminute then multiply both sides by 41 to get (41/60) degree = 41 arcminutes
jdoe0001
  • jdoe0001
hmm actually, my calculator takes the minutes for the trig functions
jdoe0001
  • jdoe0001
but you could convert it to decimals, and just use the flat degree
anonymous
  • anonymous
Give me .6833->
jim_thompson5910
  • jim_thompson5910
so that means `18°41'` is equivalent to `18.6833°` approximately
anonymous
  • anonymous
\[\tan (18.6833)=\frac{ x }{ 991 }\]
anonymous
  • anonymous
Then I just solve for x
jim_thompson5910
  • jim_thompson5910
correct
anonymous
  • anonymous
Thank you
jim_thompson5910
  • jim_thompson5910
what value of x do you get
anonymous
  • anonymous
335ft
jim_thompson5910
  • jim_thompson5910
yep I'm getting 335.113085763609 which rounds to 335
anonymous
  • anonymous
mhm Thank you for the help
jim_thompson5910
  • jim_thompson5910
you're welcome

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