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BloomLocke367

  • one year ago

\[2x^2-5x+2=(x-3)(x-2)+3x\]

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  1. BloomLocke367
    • one year ago
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    @jdoe0001 Help again?

  2. marihelenh
    • one year ago
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    The first thing you need to do is multiply out the parenthesis on the right side.

  3. BloomLocke367
    • one year ago
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    I know... I already got it down to \(x^2-3x-4=0\)

  4. BloomLocke367
    • one year ago
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    wait... I don't need help

  5. BloomLocke367
    • one year ago
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    lol

  6. BloomLocke367
    • one year ago
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    sorry XD

  7. marihelenh
    • one year ago
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    Well good then.

  8. jdoe0001
    • one year ago
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    To see what is in front of one's nose needs a constant struggle. ~~ George Orwell, "In Front of Your Nose" ~~

  9. BloomLocke367
    • one year ago
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    That's easily factorable and you get (x-4)(x+1) so your zeros are 4 and -1

  10. BloomLocke367
    • one year ago
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    well... (x-4)(x+1)=0

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spraguer (Moderator)
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