BloomLocke367
  • BloomLocke367
Hmmm...this is a dumb question, but to get rid of a fraction in an equation, do you multiply everything by the denominator of the fraction, or the reciprocal?
Mathematics
katieb
  • katieb
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BloomLocke367
  • BloomLocke367
@jdoe0001 lol sorry for bothering you
anonymous
  • anonymous
no question is a dumb question
Nnesha
  • Nnesha
you would multiply `with the reciprocal` of the denominator

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BloomLocke367
  • BloomLocke367
It is when you're in precal honors and can't remember basic math rules lol XD
BloomLocke367
  • BloomLocke367
thank you
Nnesha
  • Nnesha
\[\huge\rm \frac{ \frac{ a }{ b } }{ \frac{ c }{ d } }=\frac{ a }{ b } \times \frac{ d }{ c }\]
anonymous
  • anonymous
haha
anonymous
  • anonymous
im honers to
Nnesha
  • Nnesha
nice!
anonymous
  • anonymous
:3
jdoe0001
  • jdoe0001
there was a fellow the other day here he said he knew physics, but never seen a logarithm :|
jdoe0001
  • jdoe0001
go figure
anonymous
  • anonymous
r u Muslim Nnesha
anonymous
  • anonymous
i am
BloomLocke367
  • BloomLocke367
So I have \(x^2-7x-\frac{3}{4}=0\), and to get rid of that fraction I'd multiply everything} by \(\frac{4}{3}\)?
Nnesha
  • Nnesha
ahh no!
BloomLocke367
  • BloomLocke367
wait...you said reciprocal of the denominator... so 1/4
BloomLocke367
  • BloomLocke367
yes, no, maybe so?
BloomLocke367
  • BloomLocke367
Oh, and @jdoe0001, I'm taking AP Physics right now XD I love it
Nnesha
  • Nnesha
yes right
BloomLocke367
  • BloomLocke367
That just creates more fractions D:
Nnesha
  • Nnesha
:3 x^2-7x-\frac{ 3 }{ 4} \times \frac{1}{4} \[x^2-7x-\frac{ 3 }{ 4} \times \frac{1}{4} \] don't see any points to get more messy stuff :P
triciaal
  • triciaal
there are no dumb questions!!!!
Nnesha
  • Nnesha
i didn't noticed it's 1/4 not 4/3
anonymous
  • anonymous
thats what i sayed
BloomLocke367
  • BloomLocke367
I dunno...
Nnesha
  • Nnesha
ignore me plz :(
BloomLocke367
  • BloomLocke367
ummm... okay. I guess I'll just ask Mrs. Dunn tomorrow
Nnesha
  • Nnesha
no wait don't close !
anonymous
  • anonymous
nesha r u muslim i am
BloomLocke367
  • BloomLocke367
Please don't put spam on my question. >.<
jdoe0001
  • jdoe0001
\(\bf x^2-7x-\frac{3}{4}=0\implies 4\left( x^2-7x-\frac{3}{4} \right)=4(0) \\ \quad \\ 4x^2-21x-\cancel{4}\cdot \cfrac{3}{\cancel{4}}=0\implies 4x^2-21x-3=0\)
triciaal
  • triciaal
to get rid of a fraction in an equation, do you multiply everything by the denominator of the fraction, or the reciprocal? you multiply everything by the lowest common denominator
jdoe0001
  • jdoe0001
hmmm rather \(\bf x^2-7x-\frac{3}{4}=0\implies 4\left( x^2-7x-\frac{3}{4} \right)=4(0) \\ \quad \\ 4x^2-28x-\cancel{4}\cdot \cfrac{3}{\cancel{4}}=0\implies 4x^2-28x-3=0\)
BloomLocke367
  • BloomLocke367
OKAY THANK YOU OMG.
triciaal
  • triciaal
remember the denominator of a whole number is 1
triciaal
  • triciaal
you are welcome
BloomLocke367
  • BloomLocke367
\(\color{#0cbb34}{\text{Originally Posted by}}\) @triciaal remember the denominator of a whole number is 1 \(\color{#0cbb34}{\text{End of Quote}}\) Yes, I know :D
Nnesha
  • Nnesha
fraction in the equation i was doing totally different thin'!
Nnesha
  • Nnesha
srry about that
BloomLocke367
  • BloomLocke367
It's okay :) thanks guys

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