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x=2 y=3 y=0 z=0 x^2+y^2=4 z= 0
What is it exactly asking me to do?
For the first problem, how would you describe (in 3D space) the set of all points (x,y,z) where x=2 and y=3?
It would be in the xy plane
Would it? If x=2 and y=3 are the only requirements, then couldn't z be anything?
It would be in the xy plane perpendicular to the z
Here's what the point (2,3,0) would look like, right? |dw:1440633913751:dw|
And here's x=2, y=3, z=anything |dw:1440634022753:dw|
So it would be in the xyz plane?
The xz plane
All three of the problems are in 3D space (not necessarily in a single "plane"). I think what they're looking for in the first one is: "A line perpendicular to the xy-plane at x=2, y=3"
The line through (2,3,0) is parallel to the z-axis
@DDCamp why wouldn't it just be a line segment origin to point (2,3)
How did they get that
@Ashley1nOnly It is parallel to the z-axis, but the z-axis is perpendicular to the xy-plane. It's two ways of saying the same thing.
@triciaal The problem says "set of points in space whose coordinates satisfy the given pairs of equations." The points on the line segment you described don't satisfy the conditions that x=2 and y=3.
of course it does (2,3,0) (x,y,z)
The line through (2,3,0) is parallel to the z-axis was the answer. How is it parallel to the z-axis, it looks perpendicular
So it in the xy plane and its parallel to the z axis
The next one is it on the x plane?
the last one a circle in the xy plane