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x=2 y=3
y=0 z=0
x^2+y^2=4 z= 0

What is it exactly asking me to do?

It would be in the xy plane

Would it? If x=2 and y=3 are the only requirements, then couldn't z be anything?

It would be in the xy plane perpendicular to the z

Here's what the point (2,3,0) would look like, right?
|dw:1440633913751:dw|

Yes

And here's x=2, y=3, z=anything
|dw:1440634022753:dw|

So it would be in the xyz plane?

The xz plane

The line through (2,3,0) is parallel to the z-axis

How did they get that

of course it does (2,3,0) (x,y,z)

So it in the xy plane and its parallel to the z axis

The next one is it on the x plane?

the last one a circle in the xy plane