## BloomLocke367 one year ago I only have two left that I'm a little unclear on.

1. BloomLocke367

$$x+1-2\sqrt{x+4}=0$$

2. BloomLocke367

I have to solve that too

3. BloomLocke367

I know the 4 can come out of the radical

4. Nnesha

no

5. Nnesha

it's (x+4)

6. BloomLocke367

ohhhhhhhhhhhh

7. Nnesha

you can't separate it :(

8. BloomLocke367

yeah, when you wrote it that way I noticed.

9. Nnesha

so move all the terms to the right side instead sqrt{(x+4}

10. BloomLocke367

Why am I moving them?

11. Nnesha

you need to get sqrt{x+4} one one side and all other terms to opposite side so then you can take square both sides to cancel out the square root

12. BloomLocke367

OH THAT MAKES SENSE

13. BloomLocke367

i have $$\frac{1}{2}x+\frac{1}{2}=\sqrt{x+4}$$

14. BloomLocke367

right?

15. Nnesha

looks right

16. BloomLocke367

so $$x+4=\frac{1}{4}x+\frac{1}{4}$$, right?

17. Nnesha

mhmm

18. BloomLocke367

so 0.75x=-3.75?

19. Nnesha

there is an easier way to do it

20. Nnesha

i hate fractions :P $\huge\rm x+1-2\sqrt{x+4}=0$ move the x+1 to the right side

21. BloomLocke367

$$-2\sqrt{x+4}=-x-1$$

22. Nnesha

looks good now move the -2 to the right side remember we need just radical sign on one side

23. BloomLocke367

24. Nnesha

$$\color{Red}{-2}\sqrt{x+4}=-x-1$$ we just need radical at left side

25. BloomLocke367

oops

26. BloomLocke367

$$\sqrt{x+4}=\frac{1}{2}x+\frac{1}{2}$$

27. BloomLocke367

but, look:$$\color{#0cbb34}{\text{Originally Posted by}}$$ @BloomLocke367 i have $$\frac{1}{2}x+\frac{1}{2}=\sqrt{x+4}$$ $$\color{#0cbb34}{\text{End of Quote}}$$ I already did that

28. Nnesha

yes $\sqrt{x+4}=\frac{ (x+1) }{ 2 }$ which is same as 1/2x+1/2 but keep that to one fraction

29. Nnesha

when we finish with this question please pnch on my forehead okay

30. BloomLocke367

hahaha okay XD

31. Nnesha

that's right but i don't how u got the negative sign

32. Nnesha

i'm sorry i'm tired actually so i apologies

33. Nnesha

okay so how would you cancel out the square root ?

34. BloomLocke367

square both sides

35. Nnesha

yes right

36. BloomLocke367

so $$x+4=\frac{1}{4}x+\frac{1}{4}$$

37. BloomLocke367

38. Nnesha

$\sqrt{x+4}= (\frac{x+1 }{ 2 })^2$ that's how you should take square root at left side

39. BloomLocke367

so $$x+4=\frac{x^2+1}{4}$$

40. Nnesha

that's why i said it's better to combine them together and no

41. BloomLocke367

*facepalm*

42. Nnesha

$\huge\rm (\frac{ x+1 }{ 2 }) = \frac{ (x+1)^2 }{ 2^2 }$ both should be squared

43. BloomLocke367

sorry, everyone is talking around me and I just found out my boyfriend is in the ER... I'm a little distracted

44. Nnesha

mah don't facepalm :P

45. Nnesha

it's okay! :=)

46. BloomLocke367

oh right, that makes sense

47. BloomLocke367

x+2x+1 should be the numerator, right?

48. Nnesha

right now (x+1)^2 is same as (x+1)(x+1) you're an expert when it comes to foil method

49. Nnesha

typo

50. Nnesha

you sure it's x+2x +1 ?

51. BloomLocke367

X^2

52. BloomLocke367

UGH sorry

53. Nnesha

yes right :=) $x+4=\frac{ x^2+2x+1 }{ 4 }$ now oslve for x

54. Nnesha

solve*

55. BloomLocke367

4x+16=x^2+2x+1?

56. BloomLocke367

57. Nnesha

:=)

58. Nnesha

yes that's right

59. BloomLocke367

okay. so x^2-2x-15?

60. Nnesha

mhmm error!

61. BloomLocke367

what?

62. BloomLocke367

what error?

63. Nnesha

$\color{ReD}{4x}+16=x^2\color{ReD}{+}2x+1$

64. Nnesha

you would subtract 2x both sides right so 4x-2x = 2x not -2x :=)

65. Nnesha

$$\color{blue}{\text{Originally Posted by}}$$ @BloomLocke367 okay. so x^2-2x-15? $$\color{blue}{\text{End of Quote}}$$ so it's $\huge\rm x^2+2x-15=0$

66. BloomLocke367

no... 2x-4x=-2x

67. Nnesha

facedesk**

68. Nnesha

i moved all the terms to the left side why i'm still looking on it you're right god:(

69. BloomLocke367

hahaha, we both are having a tough time

70. BloomLocke367

meanwhile, I'm about to have a meltdown because I'm so worried...

71. BloomLocke367

anyhoo, I have (x-5)(x+3)=0

72. Nnesha

ah my fault

73. BloomLocke367

so my zeros are 5 and -3, right?

74. Nnesha

yes right solve for x and what is the statement ? you have to find solutions right ?

75. BloomLocke367

yep

76. BloomLocke367

which I found

77. Nnesha

make sure you check your work plugin 5 and -3 into the equation

78. Nnesha

there can be an extraneous solution!

79. BloomLocke367

yea, I know. I just have one more.. then I can go and quietly breakdown in my room. ;-;

80. Nnesha

i'm pretty you don't want to help anymore ahahhah

81. BloomLocke367

5 works. just checked

82. Nnesha

me*

83. Nnesha

yes right -3 is an extraneous

84. BloomLocke367

yep

85. Nnesha

alright good luck btw what's ur next question ?

86. BloomLocke367

$$\sqrt x+x=1$$

87. Nnesha

is it okay if we do it on this thread ??

88. BloomLocke367

yea, I don't mind. I just wanna get this done

89. Nnesha

okay cool! that's the easy one just like we did move the x to the right side (bec we need the radical one side )

90. BloomLocke367

$$\sqrt x=-x+1$$

91. Nnesha

yes right take square both sides $(\sqrt{x})^2= (-x+1)^2$

92. Nnesha

(-x+1)(-x+1) =foil

93. BloomLocke367

x=x^2-2x+1

94. Nnesha

right solve for x :=)

95. BloomLocke367

I'm drawing a blank here, you know why. should I factor the right side, or move the x on the left to the right?

96. Nnesha

well should move the x to the right side cuz there are like terms that we can combine

97. BloomLocke367

ok

98. Nnesha

if you factor right side that will not help you you still have to distribute factors with x

99. BloomLocke367

x^2-3x+1

100. Nnesha

yes right you need to apply quadratic formula to find x

101. BloomLocke367

ok

102. BloomLocke367

I can do that

103. BloomLocke367

gimme a moment

104. Nnesha

cuz one is the only one factor of 1 so 1 time 1 there is not way you can get 3 from 1+1

105. Nnesha

106. BloomLocke367

yea I know gimme a sec

107. BloomLocke367

so far I have $$x=\frac{3\pm\sqrt5}{2}$$

108. BloomLocke367

that's as far as I'm going

109. BloomLocke367

is that right?

110. BloomLocke367

@Nnesha

111. Nnesha

looks right!

112. BloomLocke367

ok. I'm leaving it as is

113. BloomLocke367

I'm gonna go now, thanks for your help. Goodbye!

114. Nnesha

alright good luck!