If it requires 48.3 milliliters of 0.55 molar nitric acid to neutralize 15.0 milliliters of barium hydroxide, solve for the molarity of the barium hydroxide solution. Show all of the work used to solve this problem. Unbalanced equation: Ba(OH)2 + HNO3 yields Ba(NO3)2 + H2O

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If it requires 48.3 milliliters of 0.55 molar nitric acid to neutralize 15.0 milliliters of barium hydroxide, solve for the molarity of the barium hydroxide solution. Show all of the work used to solve this problem. Unbalanced equation: Ba(OH)2 + HNO3 yields Ba(NO3)2 + H2O

Chemistry
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First step: You can find the moles of nitric acid using n=cv where n is the number of moles c is the concentration (aka molarity) so 0.55M v is volume and would need to be in litres not millilitres
ok im here

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Second step: Balance chemical equation using the stoichiometric coefficients relate the HNO3 to the Ba(NO3)2 Using the ratio you can convert the moles of HNO3 to moles of Ba(NO3)2
Third Step: After using the ratio you will have the moles of Ba(NO3)2 So you can use the formula c=n/v c is the concentration that you are trying to find n is the moles you found in the previous step v is the volume in litres so the 15mL but converted
ok so the balanced equation is Ba(OH)2 + 2 HNO3 = Ba(NO3)2 + 2 H2O
Yes it would be
So the ratio is 2 to 1 For every 2 moles of HNO3 there is 1 mole of Ba(NO3)2 produced
ok then what do i do
SO since the ratio is 2:1 the moles you found in step 1 you divide that by 2 to get the moles of Ba(NO3)2 and then you can carry on to step 3
C=N/V 0.55M=n/v
i thought ml was volume
mL is volume but since molarity is mol/L we have to convert the millilitres into litres 1L=1000mL
but it's not 1000 ml
That's the conversion 1mL=0.001L 48.3mL=? L
0.0483L
Yes using this and the 0.55M you can find n using the n=cv formula
0.0483*0.55=0.26565
Close I think you're missing a 0 in there
0.026565
remember to add both volumes (V1 + V2) to get your final volume
huh so 0.026565 isn't the answer?
Yes so now we look at the ratio it was 2:1 so to get the moles of Ba(NO3)2 you divide the moles you just got by 2 to get the moles of Ba(NO3)2
0.026565/2=0.0132825
Yes so that would be the moles of Ba(NO3)2 So now you put that into the formula c=n/v and as @Photon336 had said you have to use the total volume so you have to add both together and convert that from millilitres to litres
so 48.3+15.0?
Yeo together that will be the final volume of the solution
48.3+15.0=63.3 ---> 0.0633
yep
so thats the final answer?
@lovingod786 they asked for concentration i think you need the number of moles too so it has to be moles/liter
Nope you have to put it into the formula first c=n/v
ok so c=0.26565/0.0633?
0.0132825/0.0633=c
0.21
yep that would be correct
m\[M _{1}V_{1} = m _{2}V_{2} \] \[m_{2} = \frac{ M_{1}V{1} }{V_{2} }\] \[m_{2}] = moles of Ba(OH)2 \[V_{2}] = final volume.
so thats the final answer then??
??
Yep
OK THX
You is a really good tutor or teacher or helper..you know whatever you clarify yourself as but you did a really good job!
Well do not did
Haha thanks! I try my best! I'm pretty bad at explaining things but this site has made me a lot better at explaining what I mean and @Photon336 is really good at explaining things too, probably one of the better people at explaining things in this section
Yeah @Photon336 is good too when I first got here they use to help me
thanks guys

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