## anonymous one year ago If it requires 48.3 milliliters of 0.55 molar nitric acid to neutralize 15.0 milliliters of barium hydroxide, solve for the molarity of the barium hydroxide solution. Show all of the work used to solve this problem. Unbalanced equation: Ba(OH)2 + HNO3 yields Ba(NO3)2 + H2O

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1. anonymous

@taramgrant0543664 @Photon336

2. taramgrant0543664

First step: You can find the moles of nitric acid using n=cv where n is the number of moles c is the concentration (aka molarity) so 0.55M v is volume and would need to be in litres not millilitres

3. anonymous

ok im here

4. taramgrant0543664

Second step: Balance chemical equation using the stoichiometric coefficients relate the HNO3 to the Ba(NO3)2 Using the ratio you can convert the moles of HNO3 to moles of Ba(NO3)2

5. taramgrant0543664

Third Step: After using the ratio you will have the moles of Ba(NO3)2 So you can use the formula c=n/v c is the concentration that you are trying to find n is the moles you found in the previous step v is the volume in litres so the 15mL but converted

6. anonymous

ok so the balanced equation is Ba(OH)2 + 2 HNO3 = Ba(NO3)2 + 2 H2O

7. taramgrant0543664

Yes it would be

8. taramgrant0543664

So the ratio is 2 to 1 For every 2 moles of HNO3 there is 1 mole of Ba(NO3)2 produced

9. anonymous

ok then what do i do

10. taramgrant0543664

SO since the ratio is 2:1 the moles you found in step 1 you divide that by 2 to get the moles of Ba(NO3)2 and then you can carry on to step 3

11. anonymous

C=N/V 0.55M=n/v

12. anonymous

i thought ml was volume

13. taramgrant0543664

mL is volume but since molarity is mol/L we have to convert the millilitres into litres 1L=1000mL

14. anonymous

but it's not 1000 ml

15. taramgrant0543664

That's the conversion 1mL=0.001L 48.3mL=? L

16. anonymous

0.0483L

17. taramgrant0543664

Yes using this and the 0.55M you can find n using the n=cv formula

18. anonymous

0.0483*0.55=0.26565

19. taramgrant0543664

Close I think you're missing a 0 in there

20. anonymous

0.026565

21. Photon336

remember to add both volumes (V1 + V2) to get your final volume

22. anonymous

huh so 0.026565 isn't the answer?

23. taramgrant0543664

Yes so now we look at the ratio it was 2:1 so to get the moles of Ba(NO3)2 you divide the moles you just got by 2 to get the moles of Ba(NO3)2

24. anonymous

0.026565/2=0.0132825

25. taramgrant0543664

Yes so that would be the moles of Ba(NO3)2 So now you put that into the formula c=n/v and as @Photon336 had said you have to use the total volume so you have to add both together and convert that from millilitres to litres

26. anonymous

so 48.3+15.0?

27. taramgrant0543664

Yeo together that will be the final volume of the solution

28. anonymous

48.3+15.0=63.3 ---> 0.0633

29. Photon336

yep

30. anonymous

31. Photon336

@lovingod786 they asked for concentration i think you need the number of moles too so it has to be moles/liter

32. taramgrant0543664

Nope you have to put it into the formula first c=n/v

33. anonymous

ok so c=0.26565/0.0633?

34. taramgrant0543664

0.0132825/0.0633=c

35. anonymous

0.21

36. taramgrant0543664

yep that would be correct

37. Photon336

m$M _{1}V_{1} = m _{2}V_{2}$ $m_{2} = \frac{ M_{1}V{1} }{V_{2} }$ \[m_{2}] = moles of Ba(OH)2 \[V_{2}] = final volume.

38. anonymous

so thats the final answer then??

39. anonymous

??

40. taramgrant0543664

Yep

41. anonymous

OK THX

42. anonymous

You is a really good tutor or teacher or helper..you know whatever you clarify yourself as but you did a really good job!

43. anonymous

Well do not did

44. taramgrant0543664

Haha thanks! I try my best! I'm pretty bad at explaining things but this site has made me a lot better at explaining what I mean and @Photon336 is really good at explaining things too, probably one of the better people at explaining things in this section

45. anonymous

Yeah @Photon336 is good too when I first got here they use to help me

46. Photon336

thanks guys