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anonymous

  • one year ago

If it requires 48.3 milliliters of 0.55 molar nitric acid to neutralize 15.0 milliliters of barium hydroxide, solve for the molarity of the barium hydroxide solution. Show all of the work used to solve this problem. Unbalanced equation: Ba(OH)2 + HNO3 yields Ba(NO3)2 + H2O

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  1. anonymous
    • one year ago
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    @taramgrant0543664 @Photon336

  2. taramgrant0543664
    • one year ago
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    First step: You can find the moles of nitric acid using n=cv where n is the number of moles c is the concentration (aka molarity) so 0.55M v is volume and would need to be in litres not millilitres

  3. anonymous
    • one year ago
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    ok im here

  4. taramgrant0543664
    • one year ago
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    Second step: Balance chemical equation using the stoichiometric coefficients relate the HNO3 to the Ba(NO3)2 Using the ratio you can convert the moles of HNO3 to moles of Ba(NO3)2

  5. taramgrant0543664
    • one year ago
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    Third Step: After using the ratio you will have the moles of Ba(NO3)2 So you can use the formula c=n/v c is the concentration that you are trying to find n is the moles you found in the previous step v is the volume in litres so the 15mL but converted

  6. anonymous
    • one year ago
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    ok so the balanced equation is Ba(OH)2 + 2 HNO3 = Ba(NO3)2 + 2 H2O

  7. taramgrant0543664
    • one year ago
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    Yes it would be

  8. taramgrant0543664
    • one year ago
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    So the ratio is 2 to 1 For every 2 moles of HNO3 there is 1 mole of Ba(NO3)2 produced

  9. anonymous
    • one year ago
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    ok then what do i do

  10. taramgrant0543664
    • one year ago
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    SO since the ratio is 2:1 the moles you found in step 1 you divide that by 2 to get the moles of Ba(NO3)2 and then you can carry on to step 3

  11. anonymous
    • one year ago
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    C=N/V 0.55M=n/v

  12. anonymous
    • one year ago
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    i thought ml was volume

  13. taramgrant0543664
    • one year ago
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    mL is volume but since molarity is mol/L we have to convert the millilitres into litres 1L=1000mL

  14. anonymous
    • one year ago
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    but it's not 1000 ml

  15. taramgrant0543664
    • one year ago
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    That's the conversion 1mL=0.001L 48.3mL=? L

  16. anonymous
    • one year ago
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    0.0483L

  17. taramgrant0543664
    • one year ago
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    Yes using this and the 0.55M you can find n using the n=cv formula

  18. anonymous
    • one year ago
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    0.0483*0.55=0.26565

  19. taramgrant0543664
    • one year ago
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    Close I think you're missing a 0 in there

  20. anonymous
    • one year ago
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    0.026565

  21. Photon336
    • one year ago
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    remember to add both volumes (V1 + V2) to get your final volume

  22. anonymous
    • one year ago
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    huh so 0.026565 isn't the answer?

  23. taramgrant0543664
    • one year ago
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    Yes so now we look at the ratio it was 2:1 so to get the moles of Ba(NO3)2 you divide the moles you just got by 2 to get the moles of Ba(NO3)2

  24. anonymous
    • one year ago
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    0.026565/2=0.0132825

  25. taramgrant0543664
    • one year ago
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    Yes so that would be the moles of Ba(NO3)2 So now you put that into the formula c=n/v and as @Photon336 had said you have to use the total volume so you have to add both together and convert that from millilitres to litres

  26. anonymous
    • one year ago
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    so 48.3+15.0?

  27. taramgrant0543664
    • one year ago
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    Yeo together that will be the final volume of the solution

  28. anonymous
    • one year ago
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    48.3+15.0=63.3 ---> 0.0633

  29. Photon336
    • one year ago
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    yep

  30. anonymous
    • one year ago
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    so thats the final answer?

  31. Photon336
    • one year ago
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    @lovingod786 they asked for concentration i think you need the number of moles too so it has to be moles/liter

  32. taramgrant0543664
    • one year ago
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    Nope you have to put it into the formula first c=n/v

  33. anonymous
    • one year ago
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    ok so c=0.26565/0.0633?

  34. taramgrant0543664
    • one year ago
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    0.0132825/0.0633=c

  35. anonymous
    • one year ago
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    0.21

  36. taramgrant0543664
    • one year ago
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    yep that would be correct

  37. Photon336
    • one year ago
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    m\[M _{1}V_{1} = m _{2}V_{2} \] \[m_{2} = \frac{ M_{1}V{1} }{V_{2} }\] \[m_{2}] = moles of Ba(OH)2 \[V_{2}] = final volume.

  38. anonymous
    • one year ago
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    so thats the final answer then??

  39. anonymous
    • one year ago
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    ??

  40. taramgrant0543664
    • one year ago
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    Yep

  41. anonymous
    • one year ago
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    OK THX

  42. anonymous
    • one year ago
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    You is a really good tutor or teacher or helper..you know whatever you clarify yourself as but you did a really good job!

  43. anonymous
    • one year ago
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    Well do not did

  44. taramgrant0543664
    • one year ago
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    Haha thanks! I try my best! I'm pretty bad at explaining things but this site has made me a lot better at explaining what I mean and @Photon336 is really good at explaining things too, probably one of the better people at explaining things in this section

  45. anonymous
    • one year ago
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    Yeah @Photon336 is good too when I first got here they use to help me

  46. Photon336
    • one year ago
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    thanks guys

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