anonymous
  • anonymous
-2i is a zero of f(x) x^4 - 32x^2 - 144 What are the other zeros?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Help Please.
anonymous
  • anonymous
Can you help me?
anonymous
  • anonymous
??

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More answers

anonymous
  • anonymous
If -2i is a zero, then its conjugate 2i is also a zero. Multiply the factors \((x - 2i)(x+2i)\) Then divide your polynomial by the result using long division
anonymous
  • anonymous
x^2 -4i right?
anonymous
  • anonymous
and I divide that into x^4 - 32x^2 - 144?
anonymous
  • anonymous
no. Should be \(x^2-4i^2\), which is \(x^2+4\). And then divide
anonymous
  • anonymous
ok
anonymous
  • anonymous
|dw:1440636483361:dw|
anonymous
  • anonymous
Are the zeroes 2i 6 -6
anonymous
  • anonymous
yes
anonymous
  • anonymous
@peachpi please help when you can :)
anonymous
  • anonymous
Thank you!
anonymous
  • anonymous
you're welcome

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