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anonymous

  • one year ago

-2i is a zero of f(x) x^4 - 32x^2 - 144 What are the other zeros?

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  1. anonymous
    • one year ago
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    Help Please.

  2. anonymous
    • one year ago
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    Can you help me?

  3. anonymous
    • one year ago
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    ??

  4. anonymous
    • one year ago
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    If -2i is a zero, then its conjugate 2i is also a zero. Multiply the factors \((x - 2i)(x+2i)\) Then divide your polynomial by the result using long division

  5. anonymous
    • one year ago
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    x^2 -4i right?

  6. anonymous
    • one year ago
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    and I divide that into x^4 - 32x^2 - 144?

  7. anonymous
    • one year ago
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    no. Should be \(x^2-4i^2\), which is \(x^2+4\). And then divide

  8. anonymous
    • one year ago
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    ok

  9. anonymous
    • one year ago
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    |dw:1440636483361:dw|

  10. anonymous
    • one year ago
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    Are the zeroes 2i 6 -6

  11. anonymous
    • one year ago
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    yes

  12. anonymous
    • one year ago
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    @peachpi please help when you can :)

  13. anonymous
    • one year ago
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    Thank you!

  14. anonymous
    • one year ago
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    you're welcome

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