-2i is a zero of f(x) x^4 - 32x^2 - 144 What are the other zeros?

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-2i is a zero of f(x) x^4 - 32x^2 - 144 What are the other zeros?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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If -2i is a zero, then its conjugate 2i is also a zero. Multiply the factors \((x - 2i)(x+2i)\) Then divide your polynomial by the result using long division
x^2 -4i right?
and I divide that into x^4 - 32x^2 - 144?
no. Should be \(x^2-4i^2\), which is \(x^2+4\). And then divide
ok
|dw:1440636483361:dw|
Are the zeroes 2i 6 -6
yes
@peachpi please help when you can :)
Thank you!
you're welcome

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