How would I graph these after solving d. like mx+y=b d=mj+b a+b=6 solve for a:=-b+6 25a+50b=200 solve for a:=25-25b/50

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How would I graph these after solving d. like mx+y=b d=mj+b a+b=6 solve for a:=-b+6 25a+50b=200 solve for a:=25-25b/50

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I had to : 1. explain a situation/ situation. 2. Choose some variables and what each represents. 3. How I would set it up and solve algebraically. 4. Graph it
I just want to know how this would look on a graph.
Let the variable j be placed along the x axis and the variable d be placed along the y axis |dw:1440636598500:dw| we can't have a negative number of either jeans or dresses so we only focus on quadrant 1

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Other answers:

okay
for d=-j+6 you should find that when j = 0, d = 6 so (0,6) lies on the graph of d = -j+6 |dw:1440636692866:dw|
okay
also, when d = 0 is plugged into d=-j+6, you'll find that j = 6 the ordered pair (6,0) lies on the graph of d=-j+6 as well |dw:1440636769380:dw|
connect the two points with a straight line to graph d=-j+6 |dw:1440636800788:dw|
oh okay that makes sense
now onto the second equation if j = 0, then what is the value of d in d = -1/2j + 4 ?
4?
so (0,4) lies on the graph of d = -1/2j + 4 |dw:1440636989180:dw|
now if d = 0 in d = -1/2j + 4, what is the value of j ?
4?
no
oh maybe the 2?
if you plugged in j = 4 you would get d = -1/2j + 4 d = -1/2*4 + 4 d = -2 + 4 d = 2 which is not 0 like we want
same with j = 2 if you plugged in j = 2 you would get d = -1/2j + 4 d = -1/2*2 + 4 d = -1 + 4 d = 3 which is not 0 like we want
d = -1/2j + 4 0 = -1/2j + 4 -4 = -1/2j -1/2j = -4 j = -4*(-2) j = 8 so basically when j = 8, the value of d is d = 0 meaning we have the point (8,0) on the graph of d = -1/2j + 4 |dw:1440637317827:dw|
connect the two points with a straight line to graph d = -1/2j + 4 |dw:1440637159199:dw|
the two lines cross at (4,2) which is the solution to the system |dw:1440637183770:dw|
|dw:1440637218860:dw|
oh okay I see how you got 8 now. Thank you for helping me :))
you can also use https://www.desmos.com/calculator to help check your answer. It's a free online graphing calculator
oh nice thanks!
you're welcome

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