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anonymous

  • one year ago

How would I graph these after solving d. like mx+y=b d=mj+b a+b=6 solve for a:=-b+6 25a+50b=200 solve for a:=25-25b/50

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  1. anonymous
    • one year ago
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    I had to : 1. explain a situation/ situation. 2. Choose some variables and what each represents. 3. How I would set it up and solve algebraically. 4. Graph it

  2. anonymous
    • one year ago
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    I just want to know how this would look on a graph.

  3. jim_thompson5910
    • one year ago
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    Let the variable j be placed along the x axis and the variable d be placed along the y axis |dw:1440636598500:dw| we can't have a negative number of either jeans or dresses so we only focus on quadrant 1

  4. anonymous
    • one year ago
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    okay

  5. jim_thompson5910
    • one year ago
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    for d=-j+6 you should find that when j = 0, d = 6 so (0,6) lies on the graph of d = -j+6 |dw:1440636692866:dw|

  6. anonymous
    • one year ago
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    okay

  7. jim_thompson5910
    • one year ago
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    also, when d = 0 is plugged into d=-j+6, you'll find that j = 6 the ordered pair (6,0) lies on the graph of d=-j+6 as well |dw:1440636769380:dw|

  8. jim_thompson5910
    • one year ago
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    connect the two points with a straight line to graph d=-j+6 |dw:1440636800788:dw|

  9. anonymous
    • one year ago
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    oh okay that makes sense

  10. jim_thompson5910
    • one year ago
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    now onto the second equation if j = 0, then what is the value of d in d = -1/2j + 4 ?

  11. anonymous
    • one year ago
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    4?

  12. jim_thompson5910
    • one year ago
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    so (0,4) lies on the graph of d = -1/2j + 4 |dw:1440636989180:dw|

  13. jim_thompson5910
    • one year ago
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    now if d = 0 in d = -1/2j + 4, what is the value of j ?

  14. anonymous
    • one year ago
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    4?

  15. jim_thompson5910
    • one year ago
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    no

  16. anonymous
    • one year ago
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    oh maybe the 2?

  17. jim_thompson5910
    • one year ago
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    if you plugged in j = 4 you would get d = -1/2j + 4 d = -1/2*4 + 4 d = -2 + 4 d = 2 which is not 0 like we want

  18. jim_thompson5910
    • one year ago
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    same with j = 2 if you plugged in j = 2 you would get d = -1/2j + 4 d = -1/2*2 + 4 d = -1 + 4 d = 3 which is not 0 like we want

  19. jim_thompson5910
    • one year ago
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    d = -1/2j + 4 0 = -1/2j + 4 -4 = -1/2j -1/2j = -4 j = -4*(-2) j = 8 so basically when j = 8, the value of d is d = 0 meaning we have the point (8,0) on the graph of d = -1/2j + 4 |dw:1440637317827:dw|

  20. jim_thompson5910
    • one year ago
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    connect the two points with a straight line to graph d = -1/2j + 4 |dw:1440637159199:dw|

  21. jim_thompson5910
    • one year ago
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    the two lines cross at (4,2) which is the solution to the system |dw:1440637183770:dw|

  22. jim_thompson5910
    • one year ago
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    |dw:1440637218860:dw|

  23. anonymous
    • one year ago
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    oh okay I see how you got 8 now. Thank you for helping me :))

  24. jim_thompson5910
    • one year ago
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    you can also use https://www.desmos.com/calculator to help check your answer. It's a free online graphing calculator

  25. anonymous
    • one year ago
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    oh nice thanks!

  26. jim_thompson5910
    • one year ago
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    you're welcome

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