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anonymous

  • one year ago

Can someone please check my answers ?? i will fan and medal(: Using the following equation, find the center and radius of the circle. You must show all work and calculations to receive credit. x2 + 2x + y2 + 4y = 20

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  1. anonymous
    • one year ago
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    (X-h)^2 + (y - K)^2 = r^2 (x^2 + 2x + 1) + (y^2 + 2(2y) +4) = 20 + 1 + 4 (perfect squares) Next step is easy: you compare (x+1)^2 + (y+2)^2 = 5^2 with the standard form of the circle with centre (h,k) and radius r (x-h)^2+(y-k)^2 = r^2 and decide what the values of h, k and r are. From (y+2) = y-k, subtract y from both sides, so y-y+2 = y-y-k or 2=-k, multiply by -1 to get -2=k, so we have h=-1, k=-2, and r=5 From the standard equation of a circle, (x-h)^2+(y-k)^2=r^2 we therefore found center = (h,k)=-1,-2, and radius = r =5

  2. anonymous
    • one year ago
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    @zepdrix @jim_thompson5910

  3. jim_thompson5910
    • one year ago
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    I think you meant to say center = (-1,-2)

  4. jim_thompson5910
    • one year ago
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    if so, you have the correct answer

  5. anonymous
    • one year ago
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    yeah i did my bad , but is everything in the right order and everything ? and seem correct @jim_thompson5910

  6. jim_thompson5910
    • one year ago
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    everything else looks perfect. Nice work

  7. anonymous
    • one year ago
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    Thank you!

  8. jim_thompson5910
    • one year ago
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    you're welcome

  9. anonymous
    • one year ago
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    Thank you!

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