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anonymous
 one year ago
Explain SOHCAHTOA
sin=______
cos=______
tan=_______
anonymous
 one year ago
Explain SOHCAHTOA sin=______ cos=______ tan=_______

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triciaal
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440640439967:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440640548365:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1SOH CAHTOA is a "code" used to remember the trig identities this is with a right triangle the hypotenuse is always opposite the right angle and is the longest side of the triangle

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If i wanted to know sin cos and tan but in terms of not using opp hyp and adj. what would they look like?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0they would be points on the unit circle where the input was the angle, and the output for cosine is the first coordinate and for sine the second coordinate of that point

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i kind of dont understand

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if you are using the mnemonic device soh cah toa , save what i sent for later it will be a big help believe me, but you are not ready for it yet

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i just dont know what to put in the blanks in number 5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh i think they want you to say\[\sin(\theta)=\frac{y}{r},\cos(\theta)=\frac{x}{r},\tan(\theta)=\frac{y}{x}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0whoever wrote this made a very serious error however

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what was the error? It was my teacher btw lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sine is a function, it is spelled "sine" if you want to write it in function notation, it needs to be \(\sin(\theta)\) or \(\sin(\xi)\) or \(\sin(\clubsuit)\) or something with a variable in the parentheses not "sin = " which makes no sense at all

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you can tell him/her satellite said they were abusing notation which will lead to massive confusion for you down the road

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh, ill be sure to tell her. What would i label the side lying on the x axix and the vertical side??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440642321127:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440642400091:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440642460037:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0btw in the picture you have a \(\theta\) as the angle, so it should be \(\sin(\theta)\) etc also note that \(r=\sqrt{x^2+y^2}\) by pythagoras

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0all right. Thanks. can you guide me with this?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1#6 use pythagoren theorem @satellite73 has it above

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah we just anticipated that question when i said \[r=\sqrt{x^2+y^2}\] so if, for example the point was \((2,5)\) you would have \[r=\sqrt{2^2+5^2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i notice on this page at least, the \(\theta\)'s have made an appearance !

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Lol. Would i leave it dw:1440642870108:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0notice it says "no decimal"

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah. i just seen that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So #7 would be dw:1440643014145:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440643104712:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it is really \[\sin(\theta)=\frac{5}{\sqrt{29}}\] but that is not what they want as a "final answer"q

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah cause i cant leave the 29 like that.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I would have to multiply ???

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0aka "rationalize the denominator "

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{5}{\sqrt{29}}\times \frac{\sqrt{29}}{\sqrt{29}}=\frac{5\sqrt{29}}{29}\] with a tiny bit of practice you do this in your head

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440643207188:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0there should be a 29 in the denominator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sin(\theta)=\frac{5\sqrt{29}}{29}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmmm so cos (theta)= 2/29?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no \[\cos(\theta)=\frac{2}{\sqrt{29}}=\frac{2\sqrt{29}}{29}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0nice. im doing #8 now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok find r as before, then use the same ratios as before

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the negatives are messing me up when im using the ratios

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Am i suppose to us positives??

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1plot the points and pay attention to the signs

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0leave them as negative

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the tangent will be positive since you have two negatives, but the sine and cosine are negative for sure

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440644210522:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So is this correct????

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440644481593:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1now you have the CAST rule

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1dw:1440644731475:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1another mnemonic to remember what ratios are positive in which quadrant

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1A for all positive in quadrant 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@triciaal What about the S T C
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