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llroberts43

  • one year ago

I do not understand how to graph 3x-y<4. I thought I was supposed to substitute 0 for x and solve for y and then substitute 0 for y and solve for x to come up with the intercepts. When I do that I end up with y=4 (0,4) and then I end up with 3x = 4 and I don't know what to do next because 3 won't go into 4.

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  1. jim_thompson5910
    • one year ago
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    to graph 3x-y<4, we'll need to first graph 3x-y=4 which is the boundary line

  2. jim_thompson5910
    • one year ago
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    plugging in x = 0 leads to 3x-y=4 3*0-y = 4 0-y = 4 -y = 4 y = -4 so it should be (0,-4) instead of (0,4)

  3. llroberts43
    • one year ago
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    Oh, I didn't know what to do with the negative sign so i ignored it

  4. jim_thompson5910
    • one year ago
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    now let's plug in another x value, say x = 1 3x-y=4 3*1-y = 4 3-y = 4 solve for y to get y = ??

  5. llroberts43
    • one year ago
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    What do I do with the 3?

  6. jim_thompson5910
    • one year ago
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    to move that over, you subtract 3 from both sides

  7. llroberts43
    • one year ago
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    -1

  8. jim_thompson5910
    • one year ago
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    yes if x = 1, then y = -1

  9. jim_thompson5910
    • one year ago
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    so the two points (0,-4) and (1,-1) are on the graph of 3x-y=4

  10. jim_thompson5910
    • one year ago
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    plot the two points and draw a straight line through both of them. Extend the line out as far as you can in both directions

  11. llroberts43
    • one year ago
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    thank you. It's always something so small that I do wrong.

  12. jim_thompson5910
    • one year ago
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    do you know how do to the shaded region?

  13. llroberts43
    • one year ago
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    yes

  14. jim_thompson5910
    • one year ago
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    ok great, just checking

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