llroberts43
  • llroberts43
I do not understand how to graph 3x-y<4. I thought I was supposed to substitute 0 for x and solve for y and then substitute 0 for y and solve for x to come up with the intercepts. When I do that I end up with y=4 (0,4) and then I end up with 3x = 4 and I don't know what to do next because 3 won't go into 4.
Algebra
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SOLVED
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schrodinger
  • schrodinger
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jim_thompson5910
  • jim_thompson5910
to graph 3x-y<4, we'll need to first graph 3x-y=4 which is the boundary line
jim_thompson5910
  • jim_thompson5910
plugging in x = 0 leads to 3x-y=4 3*0-y = 4 0-y = 4 -y = 4 y = -4 so it should be (0,-4) instead of (0,4)
llroberts43
  • llroberts43
Oh, I didn't know what to do with the negative sign so i ignored it

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jim_thompson5910
  • jim_thompson5910
now let's plug in another x value, say x = 1 3x-y=4 3*1-y = 4 3-y = 4 solve for y to get y = ??
llroberts43
  • llroberts43
What do I do with the 3?
jim_thompson5910
  • jim_thompson5910
to move that over, you subtract 3 from both sides
llroberts43
  • llroberts43
-1
jim_thompson5910
  • jim_thompson5910
yes if x = 1, then y = -1
jim_thompson5910
  • jim_thompson5910
so the two points (0,-4) and (1,-1) are on the graph of 3x-y=4
jim_thompson5910
  • jim_thompson5910
plot the two points and draw a straight line through both of them. Extend the line out as far as you can in both directions
llroberts43
  • llroberts43
thank you. It's always something so small that I do wrong.
jim_thompson5910
  • jim_thompson5910
do you know how do to the shaded region?
llroberts43
  • llroberts43
yes
jim_thompson5910
  • jim_thompson5910
ok great, just checking

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