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anonymous
 one year ago
I need some help with displacement and vectors!!
The displacement vectors A and B shown both have magnitudes of 3 m. The direction of vector A is theta=30 degrees. Find graphically:
(a) A + B
(b) A  B
(c) B  A
(d) A2B
Report all angles counterclockwise from the positive xaxis.
anonymous
 one year ago
I need some help with displacement and vectors!! The displacement vectors A and B shown both have magnitudes of 3 m. The direction of vector A is theta=30 degrees. Find graphically: (a) A + B (b) A  B (c) B  A (d) A2B Report all angles counterclockwise from the positive xaxis.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440642477745:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2so B is pointing directly north? and has an angle of 90 degrees?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2one way is through the parallelogram method use the two vectors A and B to construct a parallelogram like so dw:1440642698082:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2I basically slid the vectors over to form the other missing sides

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2then you draw a vector from the original tail to where the other vectors meet up along the diagonal dw:1440642758813:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2that last arrow I drew is the vector A+B

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I see. So I would solve for the diagonal to get the sum of the two vectors?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2yeah you form a parallelogram and draw the diagonal to get the sum of the two vectors

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2http://hom.wdfiles.com/localfiles/roberval/ParallelogramLaw2.PNG

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The diagonal would have to be 3 m, then.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2no it's going to be a bit longer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh...How would I calculate that then? I understand the law, but..

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2this angle is 60 degrees dw:1440642977013:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2since 60+30 = 90

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2dw:1440643005737:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2dw:1440643058820:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ah, okay! Now I see. So then I would use the law of sines?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Since two sides are 3 m and from focusing on the one triangle, I've found that the other two angles are 30 degrees each.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2we have this triangle dw:1440643113916:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2use the law of cosines to find x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Whoops, sorry, that's what I meant!

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2law of cosines c^2 = a^2 + b^2  2ab*cos(C) x^2 = 3^2 + 3^2  2*3*3*cos(120) x = ???

anonymous
 one year ago
Best ResponseYou've already chosen the best response.03 times the square root of two :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0whoops. three times the square root of 3, i meant

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2yes 3*sqrt(3) is the exact length of A+B

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That makes sense. How would I then start on figuring out AB?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2A  B = A + (B) = A + (1*B) so you start with vector A and add on the opposite of vector B vector B = 1*B points in the complete opposite direction of B dw:1440643443046:dw so in this case directly south. The magnitude or length of B is the same as +B

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2and you add A and B just like before first form a parallelogram dw:1440643496154:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2then form the diagonal dw:1440643523787:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm assuming the obtuse angles in here again are 120 degrees, like in the last part?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2my drawing is way off though geogebra is showing me this (see attached)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay...so it's still the same as A + B?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2yeah more or less, you should find that angle ADF = 60 degrees from the attachment I posted above you'll use the law of cosines again c^2 = a^2 + b^2  2ab*cos(C) x^2 = 3^2 + 3^2  2*3*3*cos(60) x = ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay!! I think I got it now. Thank you!!

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2you're welcome
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