anonymous
  • anonymous
Tutoring;Mathematical Representation of a Spring
Mathematics
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anonymous
  • anonymous
Tutoring;Mathematical Representation of a Spring
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
A 2.0 kg mass is fastened to a spring with force constant of 45 N/m. The mass is held motionless by a student at a position 15 cm below the spring's natural unstretched position. When the ball is released, what is the Fnet acting on it? What is the acceleration of the ball at that point?
anonymous
  • anonymous
Here note that k constant is 45N/m as well as that from point of reference of the spring stretch is revealed to be 0.15m
anonymous
  • anonymous
First of all we need to know the net force acting on the ball before we can calculate the acceleration. The net force acting on the spring can be calculated as 45N/m*0.15m=6.75N Given that the ball weighs 2.0kg, using the equation F=ma 6.75N=(2.0kg)(x) 6.75N/2.0kg=3.375m/s Therefore the resulting acceleration when the ball is stretched is 3.375m/s.

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