steve816
  • steve816
Please help me! Find x so that the distance between the points (6, -1) and (x, 9) is 12.
Mathematics
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SOLVED
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jamiebookeater
  • jamiebookeater
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steve816
  • steve816
So far, this is what I have:\[12=\sqrt{x^2-12x+138}\] Not sure what to do from here :/
ganeshie8
  • ganeshie8
still here ?
steve816
  • steve816
Yes I'm here!

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jim_thompson5910
  • jim_thompson5910
\[\Large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}\] \[\Large 12 = \sqrt{\left(x-6\right)^2+\left(-1-9\right)^2}\] \[\Large 12 = \sqrt{\left(x-6\right)^2+\left(-10\right)^2}\] \[\Large 12 = \sqrt{x^2-12x+36+100}\] \[\Large 12 = \sqrt{x^2-12x+136}\] I'm not sure how you got 138. Did you mean 136??
steve816
  • steve816
Yeah, I meant 136
steve816
  • steve816
@ganeshie8 Please! I need a step by step guide.
ganeshie8
  • ganeshie8
square both sides, what do you get ?
ganeshie8
  • ganeshie8
\(12 = \sqrt{x^2-12x+136}\) square both sides and get \(144 = x^2-12x+136\) rearranging a bit \(x^2-12x-8=0\)
ganeshie8
  • ganeshie8
you may use quadratic formula to solve x
steve816
  • steve816
Thank you ganeshie!

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