A 2.0 kg rubber ball falling at 0.85 m/s bounces from the floor and moves upward at 0.65 m/s. If the ball was in contact with the floor for 0.15 s: what is the change in momentum of the ball? what was the impulse acting on the ball? what force did the floor exert on the ball?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

A 2.0 kg rubber ball falling at 0.85 m/s bounces from the floor and moves upward at 0.65 m/s. If the ball was in contact with the floor for 0.15 s: what is the change in momentum of the ball? what was the impulse acting on the ball? what force did the floor exert on the ball?

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

Consider the velocities as being in the same direction.
Since the 2.0kg rubber ball had acquired a velocity of 0.65m/s [upward] from falling downward at 0.85m/s [2.0kg][0.85m/s]-[2.0kg][-0.65m/s=1.7kgm/s+1.3kg/s=3.0mkg/s Therefore change in the momentum of the ball was 3.0mkg/s
To calculate the impulse, which is calculated by Impulse=Delta Momentum Impulse=3.0N/s Therefore the impulse on the ball was 3.0N/s. Note that impulse is equal to change in momentum.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

The amount of force exerted by the floor to the ball, which resulted in the chance in momentum of 3.0kgm/s, is calculated using the formula F*t=Delta P (change in momentum) Therefore, F*(0.15s)=3.0kgm/s F=3.0kgm/s/0.15s=20N Therefore the force exerted by the floor to the ball is 20N.
Forward me any questions. )

Not the answer you are looking for?

Search for more explanations.

Ask your own question