A small 1.5 kg lab cart is moving down the table at 0.25 m/s [forward]. A student drops a 1.0 kg brick vertically on it so that the brick and cart continue moving down the table. What is the final velocity of the brick-cart combo?
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
First I calculate the momentum of the moving cart.
Since the initial momentum of the cart is 0.375kgm/s, and the 1.0kg mass object is dropped on the moving cart, not affecting the velocity to the horizontal. Therefore, according to the conservation of momentum, the initial momentum of 0.375km/s will be conserved after the total mass has increased. Therefore increase in mass by 1.0kg is added to 1.5kg, making it 2.5kg.
Since the mass now became 2.5kg , and velocity is unknown
The velocity resulting from increase in mass by 1.0kg is 0.15m/s. According to conservation of momentum increase in weight only serves to slow down the velocity, but initial momentum to the horizontal is well conserved.