A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
A small 1.5 kg lab cart is moving down the table at 0.25 m/s [forward]. A student drops a 1.0 kg brick vertically on it so that the brick and cart continue moving down the table. What is the final velocity of the brickcart combo?
anonymous
 one year ago
A small 1.5 kg lab cart is moving down the table at 0.25 m/s [forward]. A student drops a 1.0 kg brick vertically on it so that the brick and cart continue moving down the table. What is the final velocity of the brickcart combo?

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0First I calculate the momentum of the moving cart. 1.5kg*0.25m/s=0.375kgm/s Since the initial momentum of the cart is 0.375kgm/s, and the 1.0kg mass object is dropped on the moving cart, not affecting the velocity to the horizontal. Therefore, according to the conservation of momentum, the initial momentum of 0.375km/s will be conserved after the total mass has increased. Therefore increase in mass by 1.0kg is added to 1.5kg, making it 2.5kg. Since the mass now became 2.5kg , and velocity is unknown (2.5kg)(v)=0.375kgm/s Therefore, v=0.15m/s The velocity resulting from increase in mass by 1.0kg is 0.15m/s. According to conservation of momentum increase in weight only serves to slow down the velocity, but initial momentum to the horizontal is well conserved.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.