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The addition of all of these forces must equal zero

|dw:1440660915883:dw|

|dw:1440660968779:dw|

The triangle is imaginary, hypotenuse is pointing towards upper right.

Right, and final velocity obtained will be hence (17.5+37.5)N/3.0kg

Now I am only left to find the direction which satisfies the vector with cosine

or so I think

Now I get it

But I think this assumes one dimensional momentum though

Two dimensions where two are canceling each other out becomes a question of finding the hypotenuse.

This is a general physics question dealing with the momentum?

Look|dw:1440661555489:dw|

|dw:1440661454515:dw|

If you mean 30 degrees south of east, just switch the angles

|dw:1440662053313:dw|

Ops.

Now left with the sine law to get the vector version of the velocity.

This was a good question

You want a difficult physics question? :P

Try this |dw:1440662683161:dw|

Angle to the horizontal?

No numbers, but a hint: Both the incline and box are accelerating

I would think that it depends on the mass of each object

and gravity being 9.8m/s^2

and mass cancels out

|dw:1440663228557:dw|

Not bad but remember the incline also has weight and a normal force |dw:1440663465987:dw|

Center mass originates from the tip of force due to gravity huh?

Man gotta love physics

Yes, but how would you calculate that using gravity?

Angle would have to be known as well because normal force decreases as the angle increases.

Good question anyhow

u can do this by 2 ways -
1) constraint relation
2)and the one that i told u :)

|dw:1440664770880:dw|