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anonymous
 one year ago
I have an unlimited supply of standard 6sided dice. What's the fewest number of dice that I have to simultaneously roll to be at least 90% likely to roll at least one 6?
anonymous
 one year ago
I have an unlimited supply of standard 6sided dice. What's the fewest number of dice that I have to simultaneously roll to be at least 90% likely to roll at least one 6?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0My understanding is, I used complementary counting and count the probability of not rolling a 6, P(6)=1/6. So the probability of not rolling a six is 11/6=5/6. Now we are given that we need 90% to be our 'successes' so the remaining 10% are our 'losses'. This means that 10% = 5/6. What do I do from here?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So, we found that 10% = 5/6 So, 1% = 5/6/10/100 = 5/6*100/10 = 500/60 = 50/6 = 25/3 Thus 90% = 25/3*90/100=2250/300 = 225/30 But this is wrong.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok so basically we are add all the probabilities of landing on a 6 until we reach 90% or .9 So the probability of landing on a 6 is 1/6 so we both agree with that So the probability of landing on 6 the first time is 1/6 The probability of landing on 6 a second is 1/6 the probability of landing on a 6 the third is 1/6 So basically is P(6)=1/6+1/6+1/6 .... = .9 So basically the formula can be arranged as follows x(1/6)=.9 Solve for x x represents how many times you roll the die Do you follow? so we then divide 0.9 by 1/6? Then round up to the nearest whole number?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok. let me do. Thankyou.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Does this means that there are 27/5 number of dices???
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