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anonymous

  • one year ago

can someone help me work through the rest of this problem(will fan+medal)

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  1. anonymous
    • one year ago
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    \[\sqrt{10}*\sqrt{8}\]

  2. anonymous
    • one year ago
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    i got it down to \[2\sqrt{2}*\sqrt{5}\]

  3. anonymous
    • one year ago
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    @pgpilot326

  4. anonymous
    • one year ago
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    well, not quite... \[\sqrt{10}\cdot \sqrt{8}=\left( \sqrt{5}\cdot \sqrt{2} \right)\cdot\left( \sqrt{4}\cdot \sqrt{2} \right)= \sqrt{4}\cdot \sqrt{2}\cdot \sqrt{2}\cdot \sqrt{5}\]Can you reduce from here?

  5. anonymous
    • one year ago
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    umm can u combine \[\sqrt{2}\sqrt{2}=\sqrt{4}\]

  6. anonymous
    • one year ago
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    yep...

  7. anonymous
    • one year ago
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    ok i think i can work the rest out thanks

  8. anonymous
    • one year ago
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    do you understand why?

  9. anonymous
    • one year ago
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    i think because theyre the same

  10. anonymous
    • one year ago
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    wait wouldnt it equal 2

  11. anonymous
    • one year ago
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    \[\sqrt{a}\cdot \sqrt{b}=\sqrt{a\cdot b}\] property of roots

  12. anonymous
    • one year ago
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    so..\[\sqrt{4}\]

  13. anonymous
    • one year ago
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    yes, but \[\sqrt{4}=2 \text{ and } \sqrt{2}\cdot \sqrt{2}=\left( \sqrt{2} \right)^2 = 2\]

  14. anonymous
    • one year ago
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    oh ok thanks for explaining : )

  15. anonymous
    • one year ago
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    https://www.mathsisfun.com/algebra/exponent-laws.html have a look...

  16. anonymous
    • one year ago
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    ok i will

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