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may i knw why do you want to find the inverse ?

It is extra practice I'm doing because I want to review some pre-cal stuff before calculus.

Did you come up this question yourself?

So far I got \[x=y(y^{4}+y^{2}+1)\]
and I don't know where to go from there.

solve \(x^5+x^3+x = 3\) and you'll get the inverse \(f^{−1}(3)\)

actually you don't need to do any work here
just notice that \(f\) eats \(f^{-1}\)

\[\require{cancel}\large{f(f^{-1}(3))\\~\\ \cancel{f}(\cancel{f^{-1}}(3)) \\~\\~\\3}\]

the inverse function "undoes" whatever the actual function does

Ahh no, just use irishboy's hint

ok thank you.

I see it now. wow. Thanks again.

np