mathmath333
  • mathmath333
Counting question
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
mathmath333
  • mathmath333
\(\large \color{black}{\begin{align} & \normalsize \text{The number of ways of dividing 20 different balloons }\hspace{.33em}\\~\\ & \normalsize \text{in two groups containing 11 and 9 balloons is ? }\hspace{.33em}\\~\\ \end{align}}\)
ganeshie8
  • ganeshie8
you choose 11 balloons for the first group the other group is automatically determined
anonymous
  • anonymous
i agree with ganeshie8

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

mathmath333
  • mathmath333
is answer 20C11
ganeshie8
  • ganeshie8
Yes, notice, that also equals 20C9 and agrees with our present problem that you could have chosen the balloons for the second group first
mathmath333
  • mathmath333
answer given is 20C11*9C9
ganeshie8
  • ganeshie8
20C11 looks correct to me! textbook answer could be wrong, doesn't make sense to m
mathmath333
  • mathmath333
but 9C9=1
ganeshie8
  • ganeshie8
lol okay i read it as 20C11*20C9 for some reason

Looking for something else?

Not the answer you are looking for? Search for more explanations.