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mathmath333

  • one year ago

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  1. mathmath333
    • one year ago
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    \(\large \color{black}{\begin{align} & \normalsize \text{The number of ways of dividing 20 different balloons }\hspace{.33em}\\~\\ & \normalsize \text{in two groups containing 11 and 9 balloons is ? }\hspace{.33em}\\~\\ \end{align}}\)

  2. ganeshie8
    • one year ago
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    you choose 11 balloons for the first group the other group is automatically determined

  3. anonymous
    • one year ago
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    i agree with ganeshie8

  4. mathmath333
    • one year ago
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    is answer 20C11

  5. ganeshie8
    • one year ago
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    Yes, notice, that also equals 20C9 and agrees with our present problem that you could have chosen the balloons for the second group first

  6. mathmath333
    • one year ago
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    answer given is 20C11*9C9

  7. ganeshie8
    • one year ago
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    20C11 looks correct to me! textbook answer could be wrong, doesn't make sense to m

  8. mathmath333
    • one year ago
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    but 9C9=1

  9. ganeshie8
    • one year ago
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    lol okay i read it as 20C11*20C9 for some reason

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