OnePieceFTW
  • OnePieceFTW
Zoe is using the figure shown below to prove Pythagorean Theorem using triangle similarity: In the given triangle ABC, angle A is 90 degrees and segment AD is perpendicular to segment BC.
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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OnePieceFTW
  • OnePieceFTW
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OnePieceFTW
  • OnePieceFTW
Which of these could be a step to prove that BC^2 = AB^2 + AC^2? By distribution, AC^2 plus AB^2 = BC multiplied by the quantity DC plus AB. By distribution, AC^2 plus AB^2 = BC multiplied by the quantity DC plus BD. By distribution, AC^2 plus AD^2 = BC multiplied by the quantity DC plus AB. By distribution, AC^2 plus AD^2 = BC multiplied by the quantity DC plus BD.
anonymous
  • anonymous
@jim_thompson5910

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anonymous
  • anonymous
Could you help me with this? Its the same question I have
jolo_yolo
  • jolo_yolo
@ParthKohli HI, can you please help me with this?
jolo_yolo
  • jolo_yolo
@phi help me with this, please?
phi
  • phi
the question is pretty nebulous. But it looks like they are using the idea that segment BC is the same as BD+DC so BC^2 = BC * BC = BC* (BD+DC)
jolo_yolo
  • jolo_yolo
so that narrows it down to answers D and B, right?
phi
  • phi
also, it seems they are using AB^2 + AC^2 = BC^2
phi
  • phi
so we have AB^2 + AC^2 = BC* (BD+DC) I'm not sure how this is a proof, but it's true.
phi
  • phi
and the other choices don't look true.
jolo_yolo
  • jolo_yolo
That makes much more sense, you're a life saver thank you so much!

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