help poor little ole me please

- anonymous

help poor little ole me please

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- schrodinger

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- anonymous

##### 1 Attachment

- anonymous

@mathmath333

- anonymous

ooh sorry i cant. i need help in something like that myself.... good luck!! :D

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## More answers

- anonymous

thnx fam

- anonymous

:)

- anonymous

@abb0t @adrynicoleb

- anonymous

@JoannaBlackwelder

- JoannaBlackwelder

Can you graph the function?

- anonymous

nop

- JoannaBlackwelder

It is in the form y=mx+b. You should be able to do this if you are in precalc/calc.

- anonymous

i just started this nw semester

- anonymous

@JoannaBlackwelder

- JoannaBlackwelder

I'm not sure what you mean. Graphing a line is algebra I.

- anonymous

i havent taken algebra one at all they said ididnt have to its not required anymore

- anonymous

@JoannaBlackwelder

- JoannaBlackwelder

What?! And you are doing limits???? What class are you in?

- anonymous

pre calc lol

- JoannaBlackwelder

That's crazy! Ok, Let me explain how to graph a line first.

- JoannaBlackwelder

f(x)=mx+b is the same as y=mx+b

- anonymous

ok

- JoannaBlackwelder

m stands for the slope, and b stands for the y intercept

- JoannaBlackwelder

The y intercept is where the graph crosses the y axis.

- JoannaBlackwelder

|dw:1440701012955:dw|

- JoannaBlackwelder

|dw:1440701034052:dw| The y intercept is how we get our first point on the line.

- JoannaBlackwelder

Does that make sense so far?

- anonymous

yep

- JoannaBlackwelder

Ok, cool. Slope is rise/run

- JoannaBlackwelder

So, we need to write our slope as a fraction.

- JoannaBlackwelder

Any ideas on how to write 5 as a fraction?

- anonymous

1/5

- JoannaBlackwelder

Close, that is the reciprocal of 5. 5 as a fraction is 5/1. Good try!

- JoannaBlackwelder

So, that tells us that the "rise" is 5 and the "run" is 1

- anonymous

correct

- JoannaBlackwelder

So, we go up 5 units and right 1 unit

- anonymous

oh

- JoannaBlackwelder

Can you try to draw the next point on the graph?

- JoannaBlackwelder

Start at the point I drew.

- JoannaBlackwelder

And go up 5 and right 1

- anonymous

|dw:1440701437474:dw|

- anonymous

like that

- JoannaBlackwelder

What coordinate did you end up at?

- anonymous

??

- JoannaBlackwelder

When you go up 5 units from -3, we get to positive 2 for y, and right 1 unit from 0, we get to 1 for x.

- JoannaBlackwelder

|dw:1440701575209:dw|

- anonymous

ohh i messed mines up

- JoannaBlackwelder

It's cool. It is tricky the first time. :-)

- JoannaBlackwelder

|dw:1440701649251:dw| And through 2 points we can draw a line.

- anonymous

ok soo im so confused is this part of my answer or is this the other thing

- JoannaBlackwelder

This is the "Graph the function" step

- anonymous

ohh ok lol

- JoannaBlackwelder

So, to find the limit, we need to look at where the graph approaches x=5 from the right and the left/

- JoannaBlackwelder

We can't see that far on the graph I drew because it is too small.

- JoannaBlackwelder

Can you try drawing it out on paper and see what you get for y when x=5?

- anonymous

umm hw and thisis soo hard

- JoannaBlackwelder

It's not so bad. For this one you don't actually have to draw the graph.

- JoannaBlackwelder

Because linear equations are continuous.

- JoannaBlackwelder

That means that you can just plug in the x value into the formula and get what y is.

- JoannaBlackwelder

Can you try that?

- anonymous

sorry im just have little time cuz i have to do some remodeling tomy garage here soon

- anonymous

how do i plug it in

- JoannaBlackwelder

Substitute 5 in for x and simplify.

- anonymous

so is it y= to 15

- JoannaBlackwelder

No, y=5*5-3
Use the order of operations to simplify

- JoannaBlackwelder

Start at the top:
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction

- JoannaBlackwelder

So multiplication comes before subtraction.

- anonymous

so y=22

- JoannaBlackwelder

Great! :-)

- JoannaBlackwelder

And for continuous functions (meaning no gaps in the graph) that is the limit.

- anonymous

are we done lol or is there more ?

- JoannaBlackwelder

That's it.

- anonymous

thank you bojangles thnx for ya help

- JoannaBlackwelder

You're welcome.

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