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anonymous

  • one year ago

help poor little ole me please

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    @mathmath333

  3. anonymous
    • one year ago
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    ooh sorry i cant. i need help in something like that myself.... good luck!! :D

  4. anonymous
    • one year ago
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    thnx fam

  5. anonymous
    • one year ago
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    :)

  6. anonymous
    • one year ago
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    @abb0t @adrynicoleb

  7. anonymous
    • one year ago
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    @JoannaBlackwelder

  8. JoannaBlackwelder
    • one year ago
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    Can you graph the function?

  9. anonymous
    • one year ago
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    nop

  10. JoannaBlackwelder
    • one year ago
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    It is in the form y=mx+b. You should be able to do this if you are in precalc/calc.

  11. anonymous
    • one year ago
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    i just started this nw semester

  12. anonymous
    • one year ago
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    @JoannaBlackwelder

  13. JoannaBlackwelder
    • one year ago
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    I'm not sure what you mean. Graphing a line is algebra I.

  14. anonymous
    • one year ago
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    i havent taken algebra one at all they said ididnt have to its not required anymore

  15. anonymous
    • one year ago
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    @JoannaBlackwelder

  16. JoannaBlackwelder
    • one year ago
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    What?! And you are doing limits???? What class are you in?

  17. anonymous
    • one year ago
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    pre calc lol

  18. JoannaBlackwelder
    • one year ago
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    That's crazy! Ok, Let me explain how to graph a line first.

  19. JoannaBlackwelder
    • one year ago
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    f(x)=mx+b is the same as y=mx+b

  20. anonymous
    • one year ago
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    ok

  21. JoannaBlackwelder
    • one year ago
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    m stands for the slope, and b stands for the y intercept

  22. JoannaBlackwelder
    • one year ago
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    The y intercept is where the graph crosses the y axis.

  23. JoannaBlackwelder
    • one year ago
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    |dw:1440701012955:dw|

  24. JoannaBlackwelder
    • one year ago
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    |dw:1440701034052:dw| The y intercept is how we get our first point on the line.

  25. JoannaBlackwelder
    • one year ago
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    Does that make sense so far?

  26. anonymous
    • one year ago
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    yep

  27. JoannaBlackwelder
    • one year ago
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    Ok, cool. Slope is rise/run

  28. JoannaBlackwelder
    • one year ago
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    So, we need to write our slope as a fraction.

  29. JoannaBlackwelder
    • one year ago
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    Any ideas on how to write 5 as a fraction?

  30. anonymous
    • one year ago
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    1/5

  31. JoannaBlackwelder
    • one year ago
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    Close, that is the reciprocal of 5. 5 as a fraction is 5/1. Good try!

  32. JoannaBlackwelder
    • one year ago
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    So, that tells us that the "rise" is 5 and the "run" is 1

  33. anonymous
    • one year ago
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    correct

  34. JoannaBlackwelder
    • one year ago
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    So, we go up 5 units and right 1 unit

  35. anonymous
    • one year ago
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    oh

  36. JoannaBlackwelder
    • one year ago
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    Can you try to draw the next point on the graph?

  37. JoannaBlackwelder
    • one year ago
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    Start at the point I drew.

  38. JoannaBlackwelder
    • one year ago
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    And go up 5 and right 1

  39. anonymous
    • one year ago
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    |dw:1440701437474:dw|

  40. anonymous
    • one year ago
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    like that

  41. JoannaBlackwelder
    • one year ago
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    What coordinate did you end up at?

  42. anonymous
    • one year ago
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    ??

  43. JoannaBlackwelder
    • one year ago
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    When you go up 5 units from -3, we get to positive 2 for y, and right 1 unit from 0, we get to 1 for x.

  44. JoannaBlackwelder
    • one year ago
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    |dw:1440701575209:dw|

  45. anonymous
    • one year ago
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    ohh i messed mines up

  46. JoannaBlackwelder
    • one year ago
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    It's cool. It is tricky the first time. :-)

  47. JoannaBlackwelder
    • one year ago
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    |dw:1440701649251:dw| And through 2 points we can draw a line.

  48. anonymous
    • one year ago
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    ok soo im so confused is this part of my answer or is this the other thing

  49. JoannaBlackwelder
    • one year ago
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    This is the "Graph the function" step

  50. anonymous
    • one year ago
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    ohh ok lol

  51. JoannaBlackwelder
    • one year ago
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    So, to find the limit, we need to look at where the graph approaches x=5 from the right and the left/

  52. JoannaBlackwelder
    • one year ago
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    We can't see that far on the graph I drew because it is too small.

  53. JoannaBlackwelder
    • one year ago
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    Can you try drawing it out on paper and see what you get for y when x=5?

  54. anonymous
    • one year ago
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    umm hw and thisis soo hard

  55. JoannaBlackwelder
    • one year ago
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    It's not so bad. For this one you don't actually have to draw the graph.

  56. JoannaBlackwelder
    • one year ago
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    Because linear equations are continuous.

  57. JoannaBlackwelder
    • one year ago
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    That means that you can just plug in the x value into the formula and get what y is.

  58. JoannaBlackwelder
    • one year ago
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    Can you try that?

  59. anonymous
    • one year ago
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    sorry im just have little time cuz i have to do some remodeling tomy garage here soon

  60. anonymous
    • one year ago
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    how do i plug it in

  61. JoannaBlackwelder
    • one year ago
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    Substitute 5 in for x and simplify.

  62. anonymous
    • one year ago
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    so is it y= to 15

  63. JoannaBlackwelder
    • one year ago
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    No, y=5*5-3 Use the order of operations to simplify

  64. JoannaBlackwelder
    • one year ago
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    Start at the top: Parentheses Exponents Multiplication Division Addition Subtraction

  65. JoannaBlackwelder
    • one year ago
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    So multiplication comes before subtraction.

  66. anonymous
    • one year ago
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    so y=22

  67. JoannaBlackwelder
    • one year ago
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    Great! :-)

  68. JoannaBlackwelder
    • one year ago
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    And for continuous functions (meaning no gaps in the graph) that is the limit.

  69. anonymous
    • one year ago
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    are we done lol or is there more ?

  70. JoannaBlackwelder
    • one year ago
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    That's it.

  71. anonymous
    • one year ago
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    thank you bojangles thnx for ya help

  72. JoannaBlackwelder
    • one year ago
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    You're welcome.

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