Destinyyyy
  • Destinyyyy
Dont remember how to do this one...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Destinyyyy
  • Destinyyyy
Solve the equation by the square root property. (x-9)^2=9
Destinyyyy
  • Destinyyyy
@Nnesha
Nnesha
  • Nnesha
square root property so you should take square root both sides to cancel out the square

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Nnesha
  • Nnesha
square root and square cancel each other out bec you can convert square root to 1/2 exponent \[\huge\rm\sqrt{x}=x^\frac{ 1 }{ 2 }\] so when you take square \[(x^\frac{ 1 }{ 2 })^2\] both 2 cancels out then you have left with just x so that's why we should take square root to cancel out square and square to cancel out the square root
Destinyyyy
  • Destinyyyy
Ummm okay?
Nnesha
  • Nnesha
so take square root both sides what did you get ?
Destinyyyy
  • Destinyyyy
Sorry but I dont understand
Nnesha
  • Nnesha
thats fine so what u didn't understand ?
Destinyyyy
  • Destinyyyy
Um basically everything you said :/
Nnesha
  • Nnesha
otay so take square root both sides to cancel out the square \[\huge\rm \sqrt{(x-9)^2}=\sqrt{9}\]
Destinyyyy
  • Destinyyyy
Ohhh okay
Destinyyyy
  • Destinyyyy
That turns into- x-9= +- 3
Destinyyyy
  • Destinyyyy
x=9 +- 3
Destinyyyy
  • Destinyyyy
The solution set is 6 and 12
Nnesha
  • Nnesha
\[\huge\rm x-9 = \pm 3\] so x-9 = -3 and x-9 =3
Nnesha
  • Nnesha
yep
Destinyyyy
  • Destinyyyy
Wow I didnt remember that at all till you showed me with the square root. Lol thank you again
Destinyyyy
  • Destinyyyy
I might be asking for more of your help later. Im on question 4 out of 23 -.-
Nnesha
  • Nnesha
ohh np and sure1

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