## Destinyyyy one year ago Dont remember how to do this one...

1. anonymous

Solve the equation by the square root property. (x-9)^2=9

2. anonymous

@Nnesha

3. Nnesha

square root property so you should take square root both sides to cancel out the square

4. Nnesha

square root and square cancel each other out bec you can convert square root to 1/2 exponent $\huge\rm\sqrt{x}=x^\frac{ 1 }{ 2 }$ so when you take square $(x^\frac{ 1 }{ 2 })^2$ both 2 cancels out then you have left with just x so that's why we should take square root to cancel out square and square to cancel out the square root

5. anonymous

Ummm okay?

6. Nnesha

so take square root both sides what did you get ?

7. anonymous

Sorry but I dont understand

8. Nnesha

thats fine so what u didn't understand ?

9. anonymous

Um basically everything you said :/

10. Nnesha

otay so take square root both sides to cancel out the square $\huge\rm \sqrt{(x-9)^2}=\sqrt{9}$

11. anonymous

Ohhh okay

12. anonymous

That turns into- x-9= +- 3

13. anonymous

x=9 +- 3

14. anonymous

The solution set is 6 and 12

15. Nnesha

$\huge\rm x-9 = \pm 3$ so x-9 = -3 and x-9 =3

16. Nnesha

yep

17. anonymous

Wow I didnt remember that at all till you showed me with the square root. Lol thank you again

18. anonymous

I might be asking for more of your help later. Im on question 4 out of 23 -.-

19. Nnesha

ohh np and sure1