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Destinyyyy

  • one year ago

Dont remember how to do this one...

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  1. Destinyyyy
    • one year ago
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    Solve the equation by the square root property. (x-9)^2=9

  2. Destinyyyy
    • one year ago
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    @Nnesha

  3. Nnesha
    • one year ago
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    square root property so you should take square root both sides to cancel out the square

  4. Nnesha
    • one year ago
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    square root and square cancel each other out bec you can convert square root to 1/2 exponent \[\huge\rm\sqrt{x}=x^\frac{ 1 }{ 2 }\] so when you take square \[(x^\frac{ 1 }{ 2 })^2\] both 2 cancels out then you have left with just x so that's why we should take square root to cancel out square and square to cancel out the square root

  5. Destinyyyy
    • one year ago
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    Ummm okay?

  6. Nnesha
    • one year ago
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    so take square root both sides what did you get ?

  7. Destinyyyy
    • one year ago
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    Sorry but I dont understand

  8. Nnesha
    • one year ago
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    thats fine so what u didn't understand ?

  9. Destinyyyy
    • one year ago
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    Um basically everything you said :/

  10. Nnesha
    • one year ago
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    otay so take square root both sides to cancel out the square \[\huge\rm \sqrt{(x-9)^2}=\sqrt{9}\]

  11. Destinyyyy
    • one year ago
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    Ohhh okay

  12. Destinyyyy
    • one year ago
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    That turns into- x-9= +- 3

  13. Destinyyyy
    • one year ago
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    x=9 +- 3

  14. Destinyyyy
    • one year ago
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    The solution set is 6 and 12

  15. Nnesha
    • one year ago
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    \[\huge\rm x-9 = \pm 3\] so x-9 = -3 and x-9 =3

  16. Nnesha
    • one year ago
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    yep

  17. Destinyyyy
    • one year ago
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    Wow I didnt remember that at all till you showed me with the square root. Lol thank you again

  18. Destinyyyy
    • one year ago
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    I might be asking for more of your help later. Im on question 4 out of 23 -.-

  19. Nnesha
    • one year ago
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    ohh np and sure1

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