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anonymous

  • one year ago

Annabelle and Navene are multiplying (4275)(4372). Annabelle's Work Navene's Work (4275)(4372) = 42 + 375 + 2 = 4577 (4275)(4372) = 42⋅375⋅2 = 46710 Is either of them correct? Explain your reasoning.

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  1. anonymous
    • one year ago
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    (4^2 7^5) (4^3 7^2)= 4^2 + ^3 7^5+ ^2 = 4^5 7^7

  2. anonymous
    • one year ago
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    annabele

  3. anonymous
    • one year ago
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    now ima do navenes

  4. freckles
    • one year ago
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    what do the carets before the numbers mean?

  5. freckles
    • one year ago
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    for example what does ^3 mean?

  6. anonymous
    • one year ago
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    (4^2 7^5) (4^3 7^2) = 4^2 x ^3 7^5 x ^2 = 4^6 7^10

  7. anonymous
    • one year ago
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    sorry

  8. anonymous
    • one year ago
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    @freckles it means like its an exponent so i guess its raised

  9. Michele_Laino
    • one year ago
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    hint:we can write this: \[\large \left( {{4^2} \cdot {7^5}} \right)\left( {{4^3} \cdot {7^2}} \right) = \left( {{4^2} \cdot {4^3}} \right)\left( {{7^5} \cdot {7^2}} \right) = {4^{2 + 3}} \cdot {7^{5 + 2}} = ...?\]

  10. freckles
    • one year ago
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    like I know what 5^2 means this is 5*5 but I have no clue what something like ^3 means

  11. anonymous
    • one year ago
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    the exponents are being added or also they are being multiplied in the other one

  12. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @77777jeannie77777 (4^2 7^5) (4^3 7^2)= 4^2 + ^3 7^5+ ^2 = 4^5 7^7 \(\color{blue}{\text{End of Quote}}\) you ate base

  13. anonymous
    • one year ago
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    whats that?

  14. anonymous
    • one year ago
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    can u see it?

  15. anonymous
    • one year ago
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    its #7

  16. Nnesha
    • one year ago
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    http://prntscr.com/89limo here what number is raising to the 3rd power that's what she is asking

  17. anonymous
    • one year ago
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    can u see the question?

  18. Nnesha
    • one year ago
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    no :(

  19. anonymous
    • one year ago
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    ugh

  20. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @77777jeannie77777 (4^2 7^5) (4^3 7^2)= 4^2 + ^3 7^5+ ^2 = 4^5 7^7 \(\color{blue}{\text{End of Quote}}\) it's 4^3 power not 4^2 ( i guess )

  21. anonymous
    • one year ago
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    wait a sec im going to see if i can make it a file

  22. anonymous
    • one year ago
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    no i cant :(

  23. anonymous
    • one year ago
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    how do i take a screenshot?

  24. Nnesha
    • one year ago
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    okay just recheck ur work #first comment

  25. anonymous
    • one year ago
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    how do i take one?

  26. anonymous
    • one year ago
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    ok wait a sec plz

  27. anonymous
    • one year ago
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  28. anonymous
    • one year ago
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    @Michele_Laino @freckles

  29. Nnesha
    • one year ago
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    okay so 4^{3+2} use parentheses so we can understand otay :=)

  30. anonymous
    • one year ago
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    ok:D

  31. anonymous
    • one year ago
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    4^(5)

  32. Michele_Laino
    • one year ago
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    as I wrote before, your expression can be rewritten as below: \[\large \left( {{4^2} \cdot {7^5}} \right)\left( {{4^3} \cdot {7^2}} \right) = \left( {{4^2} \cdot {4^3}} \right)\left( {{7^5} \cdot {7^2}} \right) = {4^{2 + 3}} \cdot {7^{5 + 2}} = ...?\]

  33. Nnesha
    • one year ago
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    when we multiply same bases we should add or multiply the exponents ?

  34. anonymous
    • one year ago
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    add?

  35. Nnesha
    • one year ago
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    yes right

  36. Michele_Laino
    • one year ago
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    yes!

  37. anonymous
    • one year ago
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    ok so michele its 4^(5) times 7^(7)

  38. anonymous
    • one year ago
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    right?

  39. Michele_Laino
    • one year ago
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    yes!

  40. anonymous
    • one year ago
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    so then when there not like bases how do u multiply it?

  41. Michele_Laino
    • one year ago
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    we have to compute the explicit value of each power and then we have to multiply them together

  42. anonymous
    • one year ago
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    whaa?

  43. Nnesha
    • one year ago
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    then you can't like for this one \[2^2 \times 3^5 \]

  44. Nnesha
    • one year ago
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    you will not see question like that one ^^ hehe

  45. anonymous
    • one year ago
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    lol

  46. Michele_Laino
    • one year ago
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    for example: \[\large \begin{gathered} \left( {{4^2} \cdot {7^5}} \right)\left( {{4^3} \cdot {7^2}} \right) = \left( {{4^2} \cdot {4^3}} \right)\left( {{7^5} \cdot {7^2}} \right) = {4^{2 + 3}} \cdot {7^{5 + 2}} = \hfill \\ \hfill \\ = 1024 \cdot 823543 = {\text{843}}{\text{,308}}{\text{,032}} \hfill \\ \end{gathered} \]

  47. anonymous
    • one year ago
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    ok nnesha i didnt understand what u said above that

  48. anonymous
    • one year ago
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    whoa!!

  49. anonymous
    • one year ago
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    so u just multiply the bases and then the exponents together right?

  50. Nnesha
    • one year ago
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    you question is when bases are not like then how would we multiply it ? if bases are not same you can't multiply or add the exponents \[2^2 \times 3^5= 2 \times 2 \times 3 \times 3 \times 3 \times 3 \times 3\]

  51. Michele_Laino
    • one year ago
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    no, I'm sorry, you have to evaluate each power first, then you have to multiply the obtained values together

  52. anonymous
    • one year ago
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    ohh then you multiply all those together?

  53. Michele_Laino
    • one year ago
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    yes!

  54. anonymous
    • one year ago
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    ooh

  55. Nnesha
    • one year ago
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    btw ur username is same as \[\huge\rm 7^5jeannie7^5\]

  56. anonymous
    • one year ago
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    haha ^.^

  57. anonymous
    • one year ago
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    so 972?

  58. Nnesha
    • one year ago
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    o^_^o

  59. Nnesha
    • one year ago
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    what 972 ?

  60. anonymous
    • one year ago
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    multiplying all of them together

  61. Nnesha
    • one year ago
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    ohh the example i gave you ? yes

  62. anonymous
    • one year ago
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    can you please do a summarry of the answer please? of the question lol

  63. Nnesha
    • one year ago
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    you already know when we multiply same bases we should `add or multiply` their exponents ?

  64. anonymous
    • one year ago
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    add

  65. Nnesha
    • one year ago
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    yes! right! so who is right anna or Navene ?

  66. anonymous
    • one year ago
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    ohh annabel

  67. Nnesha
    • one year ago
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    yes yayay! anna!

  68. anonymous
    • one year ago
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    yayyyyy thx

  69. Nnesha
    • one year ago
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    my pleasure :=) , \[\huge\rm 7^5jeannie7^5\]

  70. anonymous
    • one year ago
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    ;D

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