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anonymous
 one year ago
help on finding inverse functions!
f(x) = x^3  8
anonymous
 one year ago
help on finding inverse functions! f(x) = x^3  8

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IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0write it as \(y = x^3  8\) ad then find \(x = \ ...\) in terms of y

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i know how to do that, i added 8 to both sides but im stuck on what to do with the cubed x

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.2Have you considered a Cube Root?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0\(\sqrt[3]{27} = 3\) because \(3 \times 3 \times 3 = 27\)

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0\(\sqrt[3]{whatever}\) is the cube root of whatever

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh, so it would be f^1 (x) = 3√x + 8 with the radical going over both x and 8 or just x?

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.2Pretty much. Or, you can use a 1/3 exponent.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its a oneto one function right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im confused because i know its one of the 2 choices, both have f(1)x = 3√x + 8, but one has the radicand or whatever its called over the x ONLY, and the other has the radicand over the whole expression (x+8) which one is it?

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.2You should not be confused. Many exams have fake answers that might be plausible on first inspection. You must pick the right one.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its the one i picked

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0with the radicand going over the whole thing

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.2If you took the cube root of the whole thing, then yes. Did you?

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.2\(y = x^{3}  8\) Swap \(x = y^{3}  8\) Solve \(x + 8 = y^{3}\) \(\sqrt[3]{x + 8} = y\) Watch yourself work. Don't guess.
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