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Solve by completeing the square. 4x^2-12x-32=0
Divide the whole thing by 4 x^2-3x=8 x^2-3x+ 9/4= 8+9/4 x^2-3x+9/4= 41/4 (x-9/2)^2= 41/4 square root (x- 9/4)^2= +- Square root 41/4 x-9/4=+- square root 41/square root 4 +9/4 x=9/4+- square root 41/2

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Other answers:

It says my answers wrong but I dont get how
hmm there is a mistake :(
What?? Where??
|dw:1440711275980:dw| there should be b/2 in the parentheses not (b/2)^2
So 9/2 not 9/4 ?
\(\color{blue}{\text{Originally Posted by}}\) @Destinyyyy Divide the whole thing by 4 x^2-3x=8 x^2-3x+ 9/4= 8+9/4 x^2-3x+9/4= 41/4 (x-9/2)^2= 41/4 square root (x- 9/4)^2= +- Square root 41/4 x-9/4=+- square root 41/square root 4 +9/4 x=9/4+- square root 41/2 \(\color{blue}{\text{End of Quote}}\) so \[(x-\frac{ \color{ReD}{9} }{ 2 })^2 = \frac{ 41 }{ 4 }\] red part isn't right
what is b in the equation ?
omg -.- its suppose to be 3/2
\(\huge\color{green}{\checkmark}\)
x^2 - 3x - 8 = 0 (x - 1.5)^2 - 2.25 - 8 = 0 (x - 1.5)^2 = 10.25 x - 1.5 = +- sqrt 10.25 x = 1.5 +/- sqrt10.25
Thank you lol
great job !!! btw :=)
Thanks :) ... 12 out of 23

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