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anonymous
 one year ago
Can yall help me?
anonymous
 one year ago
Can yall help me?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0idk what that bc I cant open it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh okay I will text you back in a few..busy right now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The number of fish (f) in a fish tank increases when the number of algae blooms (a) decreases. Write the correct equation for this scenario, and solve for the number of fish when there are 4 algae blooms. Algae Blooms Fish 10 10 25 4 f = 1a; f = 4 f = .1a; f = .4 f = 100 over a; f = 25 f = 100 over a; f = 400

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1well the first answer choice is f = 1a basically f = a that is true for the first row but NOT true for the second row so hopefully you see why choice A is eliminated?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so its either c or d

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1the function is definitely 100/a

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1now plug in a = 4 to find the value of f

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1since 100/a = 100/4 = 25

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0could you help me some more with some other question

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1sure, one more

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alright you want me to put it on here

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1either way is fine

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1the table only shows g(x)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1I don't see f(x) anywhere

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it has f(x) on the graph but i dont understand this one

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1the graph doesn't show up. All I see is a table

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its a straight line up and down from1 on the graph for f(x)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1can you post a screenshot of it?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1ok go ahead and post it when you're ready

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1can you attach it where it says "attach file" under the text box?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1Thanks. That helps clear things up

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1From what I see, f(x) is a complete vertical line that will NEVER cross the y axis. So it does not have any yintercepts at all.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1Saying things like `g(x) has a larger yintercept` or `they both have the same yintercept` makes no sense

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0haha yes lol and it makes more since when i had to look at it for like 30 mins im tired now lol

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1it's a somewhat misleading question, so I can see how you got stuck

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes lol and thanks sorry about all that i was stressing out big time.Do you need help on anything?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1That's ok. There's no worries. I don't have any questions but thanks for asking.
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