## anonymous one year ago The charges on two metallic balls are 5.0 and 7.0 coulombs respectively. They are kept 1.2 meters apart. What is the force of interaction between the two?

Electric force=$electric force=\frac{ ke*q1*q2 }{ r^2 }$ Coulomb constant is ke ke is equal to 8.987 x 10^9 Nm^2/C^2 q1 is first charge so it would be 5C q2 is the second charge so it would be 7C r is the distance in meters which is 1.2m