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Destinyyyy

  • one year ago

What type of solution is this?

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  1. Destinyyyy
    • one year ago
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    Compute the discriminant. x^2-6x-5=0

  2. Destinyyyy
    • one year ago
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    Answer-> 56

  3. Destinyyyy
    • one year ago
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    I know if the answer is a negative it is no solution. And if it equals 0 it is exactly one solution.

  4. Destinyyyy
    • one year ago
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    Is this one an infinite number of real solutions? two unequal real solutions? two imaginary solutions?

  5. ChillOut
    • one year ago
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    Two unequal real solutions. Let Δ be the discriminant. If Δ<0, it has complex solutions. if Δ=0, it has one real solution. if Δ>0, it has 2 real unequal solutions.

  6. Destinyyyy
    • one year ago
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    Thank you.. For <0 I dont have that as an option

  7. Destinyyyy
    • one year ago
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    infinite number of real solutions two unequal real solutions two imaginary solutions one real solution

  8. Destinyyyy
    • one year ago
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    The one im on now has -20 as the answer

  9. Destinyyyy
    • one year ago
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    Its two imaginary solutions.. But what does the number have to be for it to be infinite number of real numbers?

  10. Destinyyyy
    • one year ago
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    @Nnesha

  11. dinamix
    • one year ago
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    u find 2 solution for this eqution ax^2+bx+c when u c is negative and a is positive

  12. anonymous
    • one year ago
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    The graph of a quadratic function is a parabola. It is impossible for there to be an infinite number of solutions, i.e. an infinite number of x-intercepts.

  13. Destinyyyy
    • one year ago
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    Okay.. So the correct answers are two unequal real solutions example--> 56 Two imaginary example --> -20 One real solution example--> 0

  14. Destinyyyy
    • one year ago
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    Thank for everyone's help

  15. anonymous
    • one year ago
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    You're welcome

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