- jagr2713

m=0 through (-9,1)

- katieb

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- jagr2713

Graph the line

- Nnesha

m= slope
so first write the equation
y=mx+b
where m is slope and b is y-intercept
substitute x and y for (-9,1) point

- Nnesha

remember
x =something you would draw vertical line (undefined slope
when slope is zero you would draw horizontal line

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## More answers

- jdoe0001

if the slope is 0
that means that \(y_2 = y_1\) so that \(y_2-y_1 = 0\)
and that only occurrs on a horizontal line

- jagr2713

So i know when its 0 its undefined and undefined is vertical line so i just graph it??

- Nnesha

when the slope is zero it wouldn't be undefined

- Nnesha

vertical line = undefined slope
horizontal line = (slope =0)

- jagr2713

ok so how do i graph this question

- Nnesha

\[\huge\rm \color{reD}{y} = m\color{red}{x}+b\]
replace m with 0
and (x,y) with the point (-9, 1) solve for b

- jdoe0001

\(slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies
\cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\implies \cfrac{0}{something}\implies 0\impliedby defined
\\ \quad \\
\begin{array}{ccllll}
x&y
\\\hline\\
-9&1\\
-1000&1\\
+1000&1\\
\pm \infty&1
\end{array}\qquad y=1\impliedby \textit{horizontal line}\)

- jagr2713

so infinity 1? i dont get the points D:

- Nnesha

\[\rm \frac{ someting }{0 }=undefined \]

- Nnesha

points ? what do you mean ? srry

- jagr2713

i have to graph it and to graph u need at least 2 points

- Nnesha

you can write an equation with one point and slope \[\huge\rm \color{reD}{y} = m\color{blue}{x}+b\]
\[\huge\rm (\color{blue}{x},\color{reD}{y})=(\color{blue}{-9},\color{red}{1})\]

- Nnesha

substitute y for 1
and x for -9
m=0 \[\huge\rm \color{reD}{1}=-9(\color{blue}{0})+b\] (b is y-intercept)
solve for b

- jagr2713

1

- Nnesha

yes right
so now we should plugthem into the original equation of slope intercept form \[\huge\rm y=0x+1\]
0 times x= 0
so you have left with y =1 that's what you should graph

- Nnesha

|dw:1440721541175:dw|
this one is pretty simple slope is 0 just draw a horizontal line where y =1

- jagr2713

|dw:1440721702698:dw|

- Nnesha

ye looks good

- Nnesha

and if the equation is \[\huge\rm y=3x+2\] to graph this equation you should always start with the y-intercept
y-intercept is a point where line intersect y-axis

- Nnesha

|dw:1440721805900:dw|
y-intercept = 2 so draw a point where y =2

- Nnesha

|dw:1440722012910:dw|
\[\rm slope =\frac{ rise }{ run }\]
in this equation slope =3/1
\[\huge\rm \frac{ rise }{ run }=\frac{ 3 }{ 1 }\]
rise =3
run=1
so i'll go 3 units up from 2 and then one unit to the left side

- Nnesha

any question ?

- jagr2713

I got it correct thanks :D

- Nnesha

np

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