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anonymous

  • one year ago

math

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  1. pooja195
    • one year ago
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    What about it?

  2. anonymous
    • one year ago
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    |dw:1440720978922:dw|

  3. jim_thompson5910
    • one year ago
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    are you familiar with the rule \[\Large x^{-k} = \frac{1}{x^k}\] ??

  4. anonymous
    • one year ago
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    no

  5. jim_thompson5910
    • one year ago
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    the rule is that if you have a negative exponent, you take the reciprocal of the base to make the exponent positive in this case,\[\Large 3^{-3} = \frac{1}{3^3}\]

  6. jim_thompson5910
    • one year ago
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    other examples \[\Large 2^{-7} = \frac{1}{2^7}\] \[\Large 9^{-4} = \frac{1}{9^4}\]

  7. jim_thompson5910
    • one year ago
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    |dw:1440721304965:dw|

  8. jim_thompson5910
    • one year ago
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    now you need to simplify the following |dw:1440721342332:dw|

  9. anonymous
    • one year ago
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    |dw:1440721303495:dw|

  10. jim_thompson5910
    • one year ago
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    is that a p? or a q? or a 9? (see circled) |dw:1440721502919:dw|

  11. anonymous
    • one year ago
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    that was a p sorry got connfused |dw:1440721443290:dw|

  12. jim_thompson5910
    • one year ago
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    ok now simplify that and you'll be done

  13. jim_thompson5910
    • one year ago
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    think of p as p/1

  14. jim_thompson5910
    • one year ago
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    |dw:1440721767667:dw|

  15. jim_thompson5910
    • one year ago
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    when dividing 2 fractions, flip the second fraction and multiply

  16. anonymous
    • one year ago
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    what would i get?

  17. anonymous
    • one year ago
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    like p=27?

  18. jim_thompson5910
    • one year ago
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    |dw:1440721912391:dw|

  19. anonymous
    • one year ago
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    2 and 27p

  20. jim_thompson5910
    • one year ago
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    |dw:1440721937428:dw|

  21. anonymous
    • one year ago
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    yea but i still get 1/27p

  22. jim_thompson5910
    • one year ago
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    \[\Large \frac{1}{27p}\] is the answer

  23. anonymous
    • one year ago
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    oh ok thank you

  24. anonymous
    • one year ago
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    if i have a diff question later ill post it

  25. jim_thompson5910
    • one year ago
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    no problem

  26. anonymous
    • one year ago
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    i need help

  27. anonymous
    • one year ago
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    |dw:1440724201473:dw|

  28. anonymous
    • one year ago
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    needs positive exponents,simplefy

  29. jim_thompson5910
    • one year ago
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    use the same rule to get |dw:1440724750331:dw|

  30. jim_thompson5910
    • one year ago
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    so you need to simplify \[\LARGE \frac{1}{(-8v)^2}*w^3\]

  31. anonymous
    • one year ago
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    so no multiplying?

  32. jim_thompson5910
    • one year ago
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    you do multiply think of the w^3 as w^3 over 1

  33. jim_thompson5910
    • one year ago
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    \[\LARGE \frac{1}{(-8v)^2}*w^3 = \frac{1}{(-8v)^2}*\frac{w^3}{1}\]

  34. jim_thompson5910
    • one year ago
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    then multiply straight across

  35. jim_thompson5910
    • one year ago
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    also, simplify (-8v)^2

  36. anonymous
    • one year ago
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    |dw:1440725573970:dw|

  37. jim_thompson5910
    • one year ago
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    it should be \[\Large \frac{w^3}{64v^2}\]

  38. jim_thompson5910
    • one year ago
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    you square the -8 to get 64 you square the v to get v^2

  39. anonymous
    • one year ago
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    ok

  40. anonymous
    • one year ago
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    what about this|dw:1440725832639:dw|

  41. jim_thompson5910
    • one year ago
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    Use the rule \[\LARGE \frac{x^a}{x^b} = x^{a-b}\]

  42. jim_thompson5910
    • one year ago
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    |dw:1440726015179:dw|

  43. jim_thompson5910
    • one year ago
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    so for example \[\Large \frac{B^{12}}{B^{8}} = B^{12-8} = B^4\] this is just an example and not the answer

  44. anonymous
    • one year ago
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    ok

  45. anonymous
    • one year ago
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    i think thats all thank you

  46. jim_thompson5910
    • one year ago
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    glad to be of help

  47. anonymous
    • one year ago
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    can i ask you 2 more questions?

  48. anonymous
    • one year ago
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    |dw:1440729886308:dw|

  49. anonymous
    • one year ago
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    @jim_thompson5910

  50. jim_thompson5910
    • one year ago
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    think of x as x^1 y as y^1 then use that last rule I posted above

  51. jim_thompson5910
    • one year ago
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    |dw:1440730407539:dw|

  52. jim_thompson5910
    • one year ago
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    do the same for y and z

  53. jim_thompson5910
    • one year ago
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    and of course, 32 over -8 = -4

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