someone kelp me please!!!!

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someone kelp me please!!!!

Physics
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Please check my second question.....
please check my method and calculations with a calculator........

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Do you not have a calculator?
is my method correct?????O_O
@IrishBoy123 can you please check my work??????:)
Part A) Her velocity relative to the short is equal: \[v=\sqrt{(1.2\frac{km}{h})^{2}+(2\frac{km}{h})^{2}} \approx 2.3\frac{km}{h}\] Which by my calculation should give you an angle of: \[\tan^{-1} (\frac{ 1.2 }{ 2 }) \approx 31^{o}\]
The method you choose for part b seems correct... using the known velocity across the river coupled with the width of the river to find the travel time.... then using that travel time to calculate the vertical distance downstream the boat has gone.
t your part one doesn't look correct......hold up let me upload the first question....:)
However for the time i found 46.08s... but this problem is using 2 significant figures so 46s is probably sufficient
it's because i think the numbers that your inputting aren't so accurate....
Crap your right I was using the wrong horizontal velocity (2 km/s) :( lemme recalc
let me upoad the first question, may take some time....
Ok I got 2.8 (rounded from 2.77) km/s and 26 degrees (rounded from 25.6)
yes 26 is what i got.
so for part b like i was saying the idea is correct, but i got different numbers (see above) that I did use the correct velocity to calculate (2.5 not 2)
try plug in those new numbers....
so in 46 seconds the boat travelled downstream a distance d=vt=(1.2*1000/3600) m/s * 46s = 15.33s or roughly 15 seconds (again 2 sig figs.... I dont know if your teacher is a stickler for that)
darn i meant meters... 15.33 or just 15 m
I did YumYum i plugged in the right numbers and am getting slightly different answers in my calulations
Ok for part c) its a little bit more involved but still not too bad hold on....
Yes YumYum i posted those corrected numbers above
let me upload my part c.....
so basically speaking part C) is looking for you to correct for the downward drift by aiming the boat upwards
please check my east and north signs, are they correct? at the bottom of the page!!!
i think it should have been (N29E), what do you think.????
don't worry about medals, your about to get plenty from me ^_^
So you correctly note the hypoteneuse is of magnitude 2.5 km/s because that is max speed of her boat... which gives you an angle of sin^-1(1.2/2.5) ~28.68~29degrees
i wrote 29degrees!!!
then you found the horizontal velocity to be 2.5^2=v^2+1.2^2 or v=sqrt(2.5^2-1.2^2)~2.19~2.2km/h
i don't know why i wrote 2.2"KM/h"
it should have been 2.2Km up in the north.....
as for the formatting of the direction.... that I am a little unsure about since it has been a while... but your angle is correct so i have to leave that to you unfortunately :(
does it all look right?!?!?!?!?
so if you take north as your main direction you would be heading at an angle 90-29=61degrees east from the north or 29degrees north from the east... something like that
So yea i agree it all looks good... so far so good
aight thanks!!! Please come online more often, i might need your help.....24/7 :"D Thanks!!!!
now part d is confusingly worded in my opinion but if I understand it correctly than it is easy... just reproduce what you did in part b using your new horizontal velocity to calculate the time to travel across the river here
since she will arrive directly at the farmers market that will be the TOTAL travel time to the farmers market using this route
it ok, i'll ask irishboy123....chill out
ok i looked back up above and in the first possible path she ended up approx 15m to the south of the market
so use her walking velocity to calculate the time it will take her to walk that distance north to the farmers market..... add it to the time it took her to cross the river... and that will give you the TOTAL time of the trip using this route
The conclusion should be clear at that point which is the best route to talk (quickest)
take*
Thanks!!
Your welcome :D
don't mind but i need to confirm with irishboy ^_^
cuz 2 is better than 1 :D
i do it all the time....:)
yea no probs i have seen irish boy he is good.... i couldve sworn i saw you two working earlier but when i saw this post again there was no content which is why i jumped in
take it easy man!!! ^_^ come more often, we need people like you here on OS!!! :)
Yea I do when I have some spare time, but i am in university currently and have my own work and research to be doing.
Thanks for all your help!!!! you sound very very smart tho!!! :)
understood!!!
Alright Thanks for everything, i hope i see you more often ^_^ Cheers!!!
Thank you :D and you are very welcome I will when I can
Yes!!!!! :D

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