## anonymous one year ago Simplify the expression

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1. anonymous

$(x ^{10}y^-5)^{1/5}\div(x^2y^3)^{1/3}$

2. anonymous

My answer is $x^{4/3}\div2y$

3. Nnesha

mhm

4. Nnesha

$\huge\rm (xy)^m = x^m \times y^m$remember this exponent rule x and y both raising to the m power

5. anonymous

Which is what I did

6. anonymous

The top became (x^2y^-1). I put the y on the bottom because it's negative. The bottom was (x^2/3y).

7. anonymous

have you got the right answer?

8. anonymous

is -5 is the power of y?

9. Nnesha

sorry my internet gt disconnected yesterday.

10. Nnesha

$$\color{blue}{\text{Originally Posted by}}$$ @ducksonquack The top became (x^2y^-1). I put the y on the bottom because it's negative. The bottom was (x^2/3y). $$\color{blue}{\text{End of Quote}}$$ how did you get 3 coefficient at the bottom ?

11. Nnesha

$\huge\rm \frac{ x^2 y^{-1} }{ x^{2 \times \frac{ 1 }{ 3 }} y^{\cancel{3} \times \frac{ 1 }{ \cancel{3}} } }$

12. Nnesha

ahhh i see it's x^{2/3}y please put the parentheses to show that (2/3) is an exponent yes that's right

13. Nnesha

$\huge\rm \frac{ x^2y^{-1} }{ x^{\frac{ 2 }{ 3 }} y^1 }$ when you divide same bases you should subtract their exponents

14. Nnesha

$$\color{blue}{\text{Originally Posted by}}$$ @ducksonquack My answer is $x^{4/3}\div2y$ $$\color{blue}{\text{End of Quote}}$$ your x exponent is right x^{4/3} is correct but it's not 2y i assume that's a typo

15. anonymous

Can you explain it to me then?