anonymous
  • anonymous
Simplify the expression
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[(x ^{10}y^-5)^{1/5}\div(x^2y^3)^{1/3}\]
anonymous
  • anonymous
My answer is \[x^{4/3}\div2y\]
Nnesha
  • Nnesha
mhm

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Nnesha
  • Nnesha
\[\huge\rm (xy)^m = x^m \times y^m\]remember this exponent rule x and y both raising to the m power
anonymous
  • anonymous
Which is what I did
anonymous
  • anonymous
The top became (x^2y^-1). I put the y on the bottom because it's negative. The bottom was (x^2/3y).
anonymous
  • anonymous
have you got the right answer?
anonymous
  • anonymous
is -5 is the power of y?
Nnesha
  • Nnesha
sorry my internet gt disconnected yesterday.
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @ducksonquack The top became (x^2y^-1). I put the y on the bottom because it's negative. The bottom was (x^2/3y). \(\color{blue}{\text{End of Quote}}\) how did you get 3 coefficient at the bottom ?
Nnesha
  • Nnesha
\[\huge\rm \frac{ x^2 y^{-1} }{ x^{2 \times \frac{ 1 }{ 3 }} y^{\cancel{3} \times \frac{ 1 }{ \cancel{3}} } }\]
Nnesha
  • Nnesha
ahhh i see it's x^{2/3}y please put the parentheses to show that (2/3) is an exponent yes that's right
Nnesha
  • Nnesha
\[\huge\rm \frac{ x^2y^{-1} }{ x^{\frac{ 2 }{ 3 }} y^1 }\] when you divide same bases you should `subtract` their exponents
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @ducksonquack My answer is \[x^{4/3}\div2y\] \(\color{blue}{\text{End of Quote}}\) your x exponent is right x^{4/3} is correct but it's not 2y i assume that's a typo
anonymous
  • anonymous
Can you explain it to me then?

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