anonymous
  • anonymous
f(x)=x^2+2x-1 g(x)=2x-4 solve 2f(x)-3g(x)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[2(\overbrace{x^2+2x-1}^{f(x)})-3(\overbrace{2x-4}^{g(x)})\] is a start, then a raft of algebra
anonymous
  • anonymous
@satellite73 2(x^2+4x-2) -(6x+12)?
anonymous
  • anonymous
the second part is right, but you should also distribute the 2 for the first parentheses then combine like terms

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anonymous
  • anonymous
oh wait, there is a mistake in the last part too
anonymous
  • anonymous
oh this stuff is so confusing lol
anonymous
  • anonymous
lets go slow then, because it should not be that hard
anonymous
  • anonymous
lets tackle \[2(x^2+2x-1)\]first distribute the 2 and remove the parentheses what do you get?
anonymous
  • anonymous
2x^2+4x-2
anonymous
  • anonymous
good, now lets put that aside and distribute the \(-3\)in \[-3(2x-4)\]
anonymous
  • anonymous
-6x+12
anonymous
  • anonymous
ok so next step is to combine like terms in \[2x^2+4x-2-6x+12\]
anonymous
  • anonymous
2x^2-2x+10
anonymous
  • anonymous
looks good to me not that hard, is it?
anonymous
  • anonymous
thats it? haha thanks
anonymous
  • anonymous
yeah, that's it, but as judge judy says "the questions get harder" yw

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