A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

f(x)=x^2+2x-1 g(x)=2x-4 solve 2f(x)-3g(x)

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[2(\overbrace{x^2+2x-1}^{f(x)})-3(\overbrace{2x-4}^{g(x)})\] is a start, then a raft of algebra

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @satellite73 2(x^2+4x-2) -(6x+12)?

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    the second part is right, but you should also distribute the 2 for the first parentheses then combine like terms

  4. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh wait, there is a mistake in the last part too

  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh this stuff is so confusing lol

  6. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    lets go slow then, because it should not be that hard

  7. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    lets tackle \[2(x^2+2x-1)\]first distribute the 2 and remove the parentheses what do you get?

  8. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    2x^2+4x-2

  9. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    good, now lets put that aside and distribute the \(-3\)in \[-3(2x-4)\]

  10. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    -6x+12

  11. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok so next step is to combine like terms in \[2x^2+4x-2-6x+12\]

  12. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    2x^2-2x+10

  13. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    looks good to me not that hard, is it?

  14. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thats it? haha thanks

  15. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah, that's it, but as judge judy says "the questions get harder" yw

  16. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.