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anonymous

  • one year ago

Two 1.5 kg billiard balls collide elastically. The white ball was travelling at 0.75 m/s and strikes the stationary red ball head-on. Determine the speeds of both balls after the collision.

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  1. anonymous
    • one year ago
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    Another tutorial here. Note that this is an elastic collision. This means that momentum is conserved throughout the collision however kinetic energy upon collision is lost to other forms of energy such as thermal energy by friction and sound energy.

  2. anonymous
    • one year ago
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    Note that both billiard balls weigh equally, namely 1.5kg. Since this is a head on collision, with equal mass, the momentum and kinetic energy is completely transferred to another ball without loss. Therefore the second billiard ball, or the red ball acquires exactly the same velocity as the first one. So the red ball gains a velocity of 0.75m/s with no energy lost whatsoever. interesting eh ?

  3. Abhisar
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @Robert136 Another tutorial here. Note that this is an `elastic collision`. This means that momentum is conserved throughout the collision however `kinetic energy upon collision is lost to other forms of energy such as thermal energy by friction and sound energy.` \(\color{blue}{\text{End of Quote}}\) In both elastic and inelastic collision momentum is conserved but kinetic energy is conserved additionally in elastic collision.

  4. anonymous
    • one year ago
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    it pretty simple i think,if the collsion is elastic so we will take this as collisions in 1-dimensional and it can be calculated by just putting values in formula http://i.imgur.com/AAk8Msz.png

  5. anonymous
    • one year ago
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    since math of both balls are equal so we will take m1 and m2=1.5 kg and velocity of first ball 0.75 m/s and other is stationary so it would be 0 and now you can solve it to find the velocities of both ball after collision

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