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anonymous
 one year ago
Check answers?
Use natural logarithms to solve the equation.
e^2x = 1.4
Round to the nearest thousandth. I have 0.168
Solve ln (3x – 6) = 4. Round to the nearest thousandth. I got 20.199 after rounding
Solve ln (2x + 3) = 7 Round to the nearest thousandth. I have 546.817 after rounding
anonymous
 one year ago
Check answers? Use natural logarithms to solve the equation. e^2x = 1.4 Round to the nearest thousandth. I have 0.168 Solve ln (3x – 6) = 4. Round to the nearest thousandth. I got 20.199 after rounding Solve ln (2x + 3) = 7 Round to the nearest thousandth. I have 546.817 after rounding

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ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1just use the definition of logarithm : \[\large e^{x}=b \implies x = \ln (b)\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1exponent = logarithm

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1In your first question, you have : \(\large e^{2x} = 1.4 \) therefore \(2x\) is the logarithm of \(1.4\). using math symbols we write it as : \[\large 2x = \ln (1.4)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh so that one was right then thanks

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1oh you have the answer already, one sec let me check

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.10.168 is correct for the first question http://www.wolframalpha.com/input/?i=ln%281.4%29%2F2

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1all your answers are correct, good job!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you for checking I appreciate it. Wasn't sure how I could do that. :)
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