Check answers? Use natural logarithms to solve the equation. e^2x = 1.4 Round to the nearest thousandth. I have 0.168 Solve ln (3x – 6) = 4. Round to the nearest thousandth. I got 20.199 after rounding Solve ln (2x + 3) = 7 Round to the nearest thousandth. I have 546.817 after rounding

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Check answers? Use natural logarithms to solve the equation. e^2x = 1.4 Round to the nearest thousandth. I have 0.168 Solve ln (3x – 6) = 4. Round to the nearest thousandth. I got 20.199 after rounding Solve ln (2x + 3) = 7 Round to the nearest thousandth. I have 546.817 after rounding

Mathematics
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just use the definition of logarithm : \[\large e^{x}=b \implies x = \ln (b)\]
exponent = logarithm
In your first question, you have : \(\large e^{2x} = 1.4 \) therefore \(2x\) is the logarithm of \(1.4\). using math symbols we write it as : \[\large 2x = \ln (1.4)\]

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oh so that one was right then thanks
oh you have the answer already, one sec let me check
0.168 is correct for the first question http://www.wolframalpha.com/input/?i=ln%281.4%29%2F2
all your answers are correct, good job!
thank you for checking I appreciate it. Wasn't sure how I could do that. :)
np:)

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