zarkam21
  • zarkam21
help pleaseee
Mathematics
jamiebookeater
  • jamiebookeater
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zarkam21
  • zarkam21
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shreehari499
  • shreehari499
Hi there! P(A and B) = P(A) + P(B) - P(A U B)
shreehari499
  • shreehari499
Now try it..

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anonymous
  • anonymous
So complicated o.O Maybe you should let me handle this shreehari :>
zarkam21
  • zarkam21
well P(a) + P(b) is equal to 1.3
anonymous
  • anonymous
The thing is, P(A U B) is not given or at least, not explicitly. U means or, btw So actually, P(A and B) = P(A) + P(B) - P(A or B)
anonymous
  • anonymous
Let's just look at the pretty circles :D|dw:1440769110134:dw|
zarkam21
  • zarkam21
Okay :]
anonymous
  • anonymous
If this represents A|dw:1440769131263:dw|
anonymous
  • anonymous
And this represents all that is B|dw:1440769176496:dw|
anonymous
  • anonymous
Which part of this drawing do you think is both A *and* B ? ^^
zarkam21
  • zarkam21
The middle part where the two circles intersect.
anonymous
  • anonymous
That's right :D|dw:1440769491252:dw| See? All you need was a little imagination ^^ That's why P(A and B) can also be written as \[\Large P(A\cap B)\]which is also read as probability of A *intersected* with B Good job ^^
zarkam21
  • zarkam21
Yup :] So it would be 0.5 +0.8 -0.3 ?
anonymous
  • anonymous
No. Just the part in the middle of the two circles, you said :)
anonymous
  • anonymous
|dw:1440769708337:dw| |dw:1440769721954:dw| |dw:1440769732308:dw| |dw:1440769790036:dw|
zarkam21
  • zarkam21
So just 0.3?
anonymous
  • anonymous
Yup
zarkam21
  • zarkam21
thats the answer?
anonymous
  • anonymous
Yes
zarkam21
  • zarkam21
Lol after all that work, it was as simple as that? :P Thanks anyways :]

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