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zarkam21

  • one year ago

help pleaseee

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  1. zarkam21
    • one year ago
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  2. shreehari499
    • one year ago
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    Hi there! P(A and B) = P(A) + P(B) - P(A U B)

  3. shreehari499
    • one year ago
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    Now try it..

  4. anonymous
    • one year ago
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    So complicated o.O Maybe you should let me handle this shreehari :>

  5. zarkam21
    • one year ago
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    well P(a) + P(b) is equal to 1.3

  6. anonymous
    • one year ago
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    The thing is, P(A U B) is not given or at least, not explicitly. U means or, btw So actually, P(A and B) = P(A) + P(B) - P(A or B)

  7. anonymous
    • one year ago
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    Let's just look at the pretty circles :D|dw:1440769110134:dw|

  8. zarkam21
    • one year ago
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    Okay :]

  9. anonymous
    • one year ago
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    If this represents A|dw:1440769131263:dw|

  10. anonymous
    • one year ago
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    And this represents all that is B|dw:1440769176496:dw|

  11. anonymous
    • one year ago
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    Which part of this drawing do you think is both A *and* B ? ^^

  12. zarkam21
    • one year ago
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    The middle part where the two circles intersect.

  13. anonymous
    • one year ago
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    That's right :D|dw:1440769491252:dw| See? All you need was a little imagination ^^ That's why P(A and B) can also be written as \[\Large P(A\cap B)\]which is also read as probability of A *intersected* with B Good job ^^

  14. zarkam21
    • one year ago
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    Yup :] So it would be 0.5 +0.8 -0.3 ?

  15. anonymous
    • one year ago
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    No. Just the part in the middle of the two circles, you said :)

  16. anonymous
    • one year ago
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    |dw:1440769708337:dw| |dw:1440769721954:dw| |dw:1440769732308:dw| |dw:1440769790036:dw|

  17. zarkam21
    • one year ago
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    So just 0.3?

  18. anonymous
    • one year ago
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    Yup

  19. zarkam21
    • one year ago
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    thats the answer?

  20. anonymous
    • one year ago
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    Yes

  21. zarkam21
    • one year ago
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    Lol after all that work, it was as simple as that? :P Thanks anyways :]

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