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zarkam21
 one year ago
help pleaseee
zarkam21
 one year ago
help pleaseee

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shreehari499
 one year ago
Best ResponseYou've already chosen the best response.0Hi there! P(A and B) = P(A) + P(B)  P(A U B)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So complicated o.O Maybe you should let me handle this shreehari :>

zarkam21
 one year ago
Best ResponseYou've already chosen the best response.1well P(a) + P(b) is equal to 1.3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The thing is, P(A U B) is not given or at least, not explicitly. U means or, btw So actually, P(A and B) = P(A) + P(B)  P(A or B)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Let's just look at the pretty circles :Ddw:1440769110134:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If this represents Adw:1440769131263:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And this represents all that is Bdw:1440769176496:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Which part of this drawing do you think is both A *and* B ? ^^

zarkam21
 one year ago
Best ResponseYou've already chosen the best response.1The middle part where the two circles intersect.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's right :Ddw:1440769491252:dw See? All you need was a little imagination ^^ That's why P(A and B) can also be written as \[\Large P(A\cap B)\]which is also read as probability of A *intersected* with B Good job ^^

zarkam21
 one year ago
Best ResponseYou've already chosen the best response.1Yup :] So it would be 0.5 +0.8 0.3 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No. Just the part in the middle of the two circles, you said :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1440769708337:dw dw:1440769721954:dw dw:1440769732308:dw dw:1440769790036:dw

zarkam21
 one year ago
Best ResponseYou've already chosen the best response.1Lol after all that work, it was as simple as that? :P Thanks anyways :]
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