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anonymous

  • one year ago

The equation f(x) = 5x2 − 30x + 6 represents a parabola. What is the vertex of the parabola? (−5, 281) (5, −19) (−3, 141) (3, −39)

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  1. triciaal
    • one year ago
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    standard ax^2 +bx + c vertex a(x-h)^2 + k

  2. Nnesha
    • one year ago
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    \[\huge\rm \frac{ -b }{ 2a }\] use this formula to find x-coordinate of the vertex then substitute all x's for its value into f(x) equation to find y-coordinate of the vertex

  3. triciaal
    • one year ago
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    vertex (h, k)

  4. anonymous
    • one year ago
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    what would i input into the formula?

  5. Nnesha
    • one year ago
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    \[\huge\rm Ax^2+Bx+C\] quadratic equation where a=leading coefficient b=middle term c=constant term

  6. Luigi0210
    • one year ago
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    There are two ways to find the vertex.. and since your equation is already in standard form, using \(\large \frac{-b}{2a} \) would be easier. unless you want to complete the square and use @triciaal 's way

  7. anonymous
    • one year ago
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    Oh, okay. Thank you, I will give you an update on how I do :D

  8. anonymous
    • one year ago
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    Well, Look at the formula, ax^2 How many x^2 numbers do you have in your equation? bx How many numbers do you have that have x? and c, your only remaing number.

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