Given ƒ(x) = 3x - 1 and g(x)= -x + 6, find ƒ(-2) + g(5). -6 6 8

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Given ƒ(x) = 3x - 1 and g(x)= -x + 6, find ƒ(-2) + g(5). -6 6 8

Mathematics
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just replace the x in f(x) ( that is 3x - 1) by -2 and work it out then replace the x in -x + 6 by 5 and work it out and add the 2 results
wait what im confused
|dw:1440782538008:dw|

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Other answers:

mathematicians are lazy, unfortunately, and function notation should really look like this: f(x) = 3(x)-1 so that whatever is in the parenthesis on the left is what should be in the parenthesis on the right. so to evaluate f(-2) you would write: f(-2) = 3(-2) -1 and then evaluate. can you evaluate this?
3(-2) - 1 = -6-1 = ?
its 6
no - 6 - 1=
3(-2) means 3 x (-2) = ?
is it 8?
try using a number line |dw:1440782788181:dw|
|dw:1440782926063:dw|
it cant be -7
-7 is the answer to f(-2) now you need to evaluate g(x) which is - 5 + 6
* g(5) i should say
ok
what is -5 + 6 ?
1
ok so now e only need to add the 2 results -7 + 1 = ?
-6
|dw:1440783216552:dw|
correct
thanks
yw

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