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countrygirl1431

  • one year ago

Given ƒ(x) = 3x - 1 and g(x)= -x + 6, find ƒ(-2) + g(5). -6 6 8

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  1. welshfella
    • one year ago
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    just replace the x in f(x) ( that is 3x - 1) by -2 and work it out then replace the x in -x + 6 by 5 and work it out and add the 2 results

  2. countrygirl1431
    • one year ago
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    wait what im confused

  3. welshfella
    • one year ago
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    |dw:1440782538008:dw|

  4. anonymous
    • one year ago
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    mathematicians are lazy, unfortunately, and function notation should really look like this: f(x) = 3(x)-1 so that whatever is in the parenthesis on the left is what should be in the parenthesis on the right. so to evaluate f(-2) you would write: f(-2) = 3(-2) -1 and then evaluate. can you evaluate this?

  5. welshfella
    • one year ago
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    3(-2) - 1 = -6-1 = ?

  6. countrygirl1431
    • one year ago
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    its 6

  7. welshfella
    • one year ago
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    no - 6 - 1=

  8. anonymous
    • one year ago
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    3(-2) means 3 x (-2) = ?

  9. countrygirl1431
    • one year ago
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    is it 8?

  10. welshfella
    • one year ago
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    try using a number line |dw:1440782788181:dw|

  11. welshfella
    • one year ago
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    |dw:1440782926063:dw|

  12. countrygirl1431
    • one year ago
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    it cant be -7

  13. welshfella
    • one year ago
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    -7 is the answer to f(-2) now you need to evaluate g(x) which is - 5 + 6

  14. welshfella
    • one year ago
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    * g(5) i should say

  15. countrygirl1431
    • one year ago
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    ok

  16. welshfella
    • one year ago
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    what is -5 + 6 ?

  17. countrygirl1431
    • one year ago
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    1

  18. welshfella
    • one year ago
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    ok so now e only need to add the 2 results -7 + 1 = ?

  19. countrygirl1431
    • one year ago
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    -6

  20. welshfella
    • one year ago
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    |dw:1440783216552:dw|

  21. welshfella
    • one year ago
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    correct

  22. countrygirl1431
    • one year ago
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    thanks

  23. welshfella
    • one year ago
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    yw

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