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BioHazard9064

  • one year ago

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  1. BioHazard9064
    • one year ago
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    A system of equations is shown below: -3x + 7y = -16 -9x + 5y = 16 Part A: Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this. Part B: Show that the equivalent system has the same solution as the original system of equations.

  2. BioHazard9064
    • one year ago
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    @triciaal hey can you help me please

  3. triciaal
    • one year ago
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    so you need to solve by elimination.

  4. BioHazard9064
    • one year ago
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    OK so how do we do that.

  5. triciaal
    • one year ago
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    the objective is to pick a variable and make the coefficient equal and opposite so that when you add the equations the sum of that variable is zero as in eliminated. you now have one equation with one variable. solve. use this value in either of the originals to get the value of the other.

  6. BioHazard9064
    • one year ago
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    so wait if this is elimination we would add them

  7. triciaal
    • one year ago
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    i will walk you through this time

  8. BioHazard9064
    • one year ago
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    to get the x then use the x to get the y

  9. triciaal
    • one year ago
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    pick a variable

  10. BioHazard9064
    • one year ago
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    x

  11. triciaal
    • one year ago
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    so to make the coefficients equal and opposite multiply the first eqn by - 3

  12. BioHazard9064
    • one year ago
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    ok so that would look something like this 9x+7y=48

  13. BioHazard9064
    • one year ago
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    am i right?

  14. triciaal
    • one year ago
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    |dw:1440782571063:dw|

  15. BioHazard9064
    • one year ago
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    do we subtract -10 with 64?

  16. triciaal
    • one year ago
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    no you forgot to multiply the 7y

  17. BioHazard9064
    • one year ago
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    -16*

  18. triciaal
    • one year ago
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    slow down and follow

  19. BioHazard9064
    • one year ago
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    ok

  20. triciaal
    • one year ago
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    now that you have y substitute in either of the originals and calculate x

  21. BioHazard9064
    • one year ago
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    wait what was our y

  22. triciaal
    • one year ago
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    it is always a good practice to check the solution in the other original because it is very very easy to make arithmetic errors.

  23. BioHazard9064
    • one year ago
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    indeed I make them all the time xD

  24. triciaal
    • one year ago
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    so what was your solution?

  25. BioHazard9064
    • one year ago
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    for what... what I said earlier?

  26. BioHazard9064
    • one year ago
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    oh wait so we were supposed to multiply the -3 *7

  27. triciaal
    • one year ago
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    yes

  28. BioHazard9064
    • one year ago
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    9x-21=48*

  29. triciaal
    • one year ago
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    |dw:1440783443270:dw|

  30. triciaal
    • one year ago
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    you forgot your y

  31. BioHazard9064
    • one year ago
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    oh yea 9x-21y=48

  32. triciaal
    • one year ago
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    |dw:1440783530804:dw|

  33. BioHazard9064
    • one year ago
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    no wait im supposed to divide sorry

  34. BioHazard9064
    • one year ago
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    y=-4 @triciaal

  35. triciaal
    • one year ago
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    now find x

  36. BioHazard9064
    • one year ago
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    -3x + 7(-4) = -16

  37. BioHazard9064
    • one year ago
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    So we would do +3x

  38. BioHazard9064
    • one year ago
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    is-int it multiplication

  39. BioHazard9064
    • one year ago
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    x=-4

  40. triciaal
    • one year ago
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    go ahead and +3x if that is easier for you the idea is to isolate the variable terms to one side and the constants to the other then divide by the coefficient of the variable

  41. BioHazard9064
    • one year ago
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    both of them are -4 right?

  42. triciaal
    • one year ago
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    correct

  43. triciaal
    • one year ago
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    solution (-4, -4)

  44. BioHazard9064
    • one year ago
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    So how would i do this ... Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this

  45. triciaal
    • one year ago
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    review everything from the beginning

  46. BioHazard9064
    • one year ago
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    ok ... I dont see it

  47. BioHazard9064
    • one year ago
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    like I see what your talking about but I dont see how that is an equivalent system

  48. BioHazard9064
    • one year ago
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    @triciaal sorry to bother you more but I dont understand

  49. triciaal
    • one year ago
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    where did you stop?

  50. BioHazard9064
    • one year ago
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    stop?

  51. triciaal
    • one year ago
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    did you review? we have a multiple of equation 1 because we multiplied by -3 we added this to the 2nd eqn equivalent system created sum means to add

  52. triciaal
    • one year ago
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    show it has the same result the solution works in each of the originals

  53. BioHazard9064
    • one year ago
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    oh yes I did and thanks so much for helping me

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