BioHazard9064
  • BioHazard9064
Help Please
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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BioHazard9064
  • BioHazard9064
A system of equations is shown below: -3x + 7y = -16 -9x + 5y = 16 Part A: Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this. Part B: Show that the equivalent system has the same solution as the original system of equations.
BioHazard9064
  • BioHazard9064
@triciaal hey can you help me please
triciaal
  • triciaal
so you need to solve by elimination.

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BioHazard9064
  • BioHazard9064
OK so how do we do that.
triciaal
  • triciaal
the objective is to pick a variable and make the coefficient equal and opposite so that when you add the equations the sum of that variable is zero as in eliminated. you now have one equation with one variable. solve. use this value in either of the originals to get the value of the other.
BioHazard9064
  • BioHazard9064
so wait if this is elimination we would add them
triciaal
  • triciaal
i will walk you through this time
BioHazard9064
  • BioHazard9064
to get the x then use the x to get the y
triciaal
  • triciaal
pick a variable
BioHazard9064
  • BioHazard9064
x
triciaal
  • triciaal
so to make the coefficients equal and opposite multiply the first eqn by - 3
BioHazard9064
  • BioHazard9064
ok so that would look something like this 9x+7y=48
BioHazard9064
  • BioHazard9064
am i right?
triciaal
  • triciaal
|dw:1440782571063:dw|
BioHazard9064
  • BioHazard9064
do we subtract -10 with 64?
triciaal
  • triciaal
no you forgot to multiply the 7y
BioHazard9064
  • BioHazard9064
-16*
triciaal
  • triciaal
slow down and follow
BioHazard9064
  • BioHazard9064
ok
triciaal
  • triciaal
now that you have y substitute in either of the originals and calculate x
BioHazard9064
  • BioHazard9064
wait what was our y
triciaal
  • triciaal
it is always a good practice to check the solution in the other original because it is very very easy to make arithmetic errors.
BioHazard9064
  • BioHazard9064
indeed I make them all the time xD
triciaal
  • triciaal
so what was your solution?
BioHazard9064
  • BioHazard9064
for what... what I said earlier?
BioHazard9064
  • BioHazard9064
oh wait so we were supposed to multiply the -3 *7
triciaal
  • triciaal
yes
BioHazard9064
  • BioHazard9064
9x-21=48*
triciaal
  • triciaal
|dw:1440783443270:dw|
triciaal
  • triciaal
you forgot your y
BioHazard9064
  • BioHazard9064
oh yea 9x-21y=48
triciaal
  • triciaal
|dw:1440783530804:dw|
BioHazard9064
  • BioHazard9064
no wait im supposed to divide sorry
BioHazard9064
  • BioHazard9064
y=-4 @triciaal
triciaal
  • triciaal
now find x
BioHazard9064
  • BioHazard9064
-3x + 7(-4) = -16
BioHazard9064
  • BioHazard9064
So we would do +3x
BioHazard9064
  • BioHazard9064
is-int it multiplication
BioHazard9064
  • BioHazard9064
x=-4
triciaal
  • triciaal
go ahead and +3x if that is easier for you the idea is to isolate the variable terms to one side and the constants to the other then divide by the coefficient of the variable
BioHazard9064
  • BioHazard9064
both of them are -4 right?
triciaal
  • triciaal
correct
triciaal
  • triciaal
solution (-4, -4)
BioHazard9064
  • BioHazard9064
So how would i do this ... Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this
triciaal
  • triciaal
review everything from the beginning
BioHazard9064
  • BioHazard9064
ok ... I dont see it
BioHazard9064
  • BioHazard9064
like I see what your talking about but I dont see how that is an equivalent system
BioHazard9064
  • BioHazard9064
@triciaal sorry to bother you more but I dont understand
triciaal
  • triciaal
where did you stop?
BioHazard9064
  • BioHazard9064
stop?
triciaal
  • triciaal
did you review? we have a multiple of equation 1 because we multiplied by -3 we added this to the 2nd eqn equivalent system created sum means to add
triciaal
  • triciaal
show it has the same result the solution works in each of the originals
BioHazard9064
  • BioHazard9064
oh yes I did and thanks so much for helping me

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