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(x-6) ^3/2 =27

I dont remember how to do this..

\[\large (x-6) ^{\frac{3}{2}} =27\]
yes?

Yeah

Um okay?

or if its simpler
https://gyazo.com/dfe8c6b9853179633b8a8fe3a0bcb746

so in \[\frac{3}{2}\] you have a cube and a square root
you want to undo them both, but one by one

\[n^{3/2} = (n^{1/2})^3 = (n^3)^{1/2}\]

and here \(n = x-6\) !!

Um all im really understanding is that n= x-6 ... Except I dont get the point of n

Yes

and \[n^{3/2} = (n^{1/2})^3\]
yes

That I dont remember

I thought im suppose to flip 3/2 to 2/3 to cancel it out and put 2/3 by the 27...

if that's how you see it, go for it. it is how you solve it.

Okay. But I dont remember what to do after that

Um its like the reciprocal of 3/2

\[n^{2/3} = (n^2)^{1/3} = \sqrt[3]{n^2}\]
and
\[n^{2/3} = (n^{1/3})^{2} = (\sqrt[3]{n})^2\]

Okay so your saying...
x-6= ^3 square root 27 ^2

sorry, don't really get that notation, just feel free to post what you think the answer is

|dw:1440786073328:dw|

looks good

Okay.. Im stuck there

https://www.google.co.uk/webhp?sourceid=chrome-instant&ion=1&espv=2&ie=UTF-8#q=calculator

|dw:1440786180440:dw|

?? Nothing is there.. Just a 0

|dw:1440786213763:dw|

729

yes, now cube root of that

Um?

https://gyazo.com/3110dd44529fb9f72a87b50ae9e8e75c

https://gyazo.com/cacad2370ac356783aa9f6f37bf6af73

did you see how i made the calculator give us the cube root?
\[\large 729^{(1 \ divided \ by\ 3)}\]

So.
x-6=9 ?

yes

Okay...
Ive been using this as an example.
https://www.youtube.com/watch?v=6Y-3mQkqEOA

x=15

yes

Okay. Im still confused but okay. Thanks