anonymous
  • anonymous
A hybrid car with a 9.80 gal tank consumes gasoline at a rate of 54.1 miles/gal. How many liters of gasoline will be consumed traveling 132 km? Is my answer correct? Will show work in a post.
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
1 mile = 5280 ft 1 ft = 12 in 1 in = 2.54 cm 100 cm = 1 m 1000 m = 1 km \[(\frac{ 54.1 miles }{ gal })(\frac{ 5280 ft }{ mile })(\frac{ 12 inches }{ ft })(\frac{ 2.54cm }{ inch })(\frac{ meter }{ 100cm })(\frac{ 132km }{ 1000m })(\frac{ 1gal }{ 3.78541 L})\] = 3036.037674 since 54.1 is 3 significant figures =3040L I got this wrong (on an online quiz) can you please tell me why. Thanks in advance
anonymous
  • anonymous
|dw:1440788328251:dw|
anonymous
  • anonymous
The (132 km/1000 m) should be (1 km/1000 m) and the unit is km/L not L

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anonymous
  • anonymous
To get L, you have to divide. |dw:1440788910353:dw|
anonymous
  • anonymous
Thanks for explaining. I redid it like this: \[132km(\frac{ 1000m }{ km })(\frac{ 100cm }{ m })(\frac{ 1 inch }{ 2.54cm })(\frac{ 1 ft }{ 12inches })(\frac{ mile }{ 5280ft })(\frac{ gal }{ 54.1mile })(\frac{ 3.78541L }{ gal })\] =5.739059L 3 significant figures = 5.74L

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