anonymous
  • anonymous
In △JKL, solve for x. Answer Choices: A) 66.73 B) 74.89 C) 15.44 D) 38.16
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
1 Attachment
Nnesha
  • Nnesha
\[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\]
Nnesha
  • Nnesha
|dw:1440790508463:dw|

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Nnesha
  • Nnesha
which function you should use to find x ?
anonymous
  • anonymous
The Cos function?
Nnesha
  • Nnesha
which side is adjacent of 27 degree angle ?
anonymous
  • anonymous
Side KL with the 34 in the middle
Nnesha
  • Nnesha
hmm that would be the opposite side adjacent side would the touch |dw:1440790695818:dw| the angle now look at 27 degree angle
Nnesha
  • Nnesha
kl is adjacent of theta it's a opposite side of 27 degree angle not adj
anonymous
  • anonymous
Oh, yes. I forgot about the Theta,
Nnesha
  • Nnesha
to find length of x you should know one angle and one side so we would use sin function
Nnesha
  • Nnesha
|dw:1440790850611:dw|
anonymous
  • anonymous
Wait, how'd you get the Adjacent onto the opposite side? Is it being flipped because of the 27 degrees?
Nnesha
  • Nnesha
different angles different sides
anonymous
  • anonymous
|dw:1440791024957:dw|
Nnesha
  • Nnesha
JK is n't opposite side of 27 angle
Nnesha
  • Nnesha
yep right solve for x
anonymous
  • anonymous
Okay, just a second :)
anonymous
  • anonymous
|dw:1440791173523:dw|
anonymous
  • anonymous
Then my answer was: 74.906
Nnesha
  • Nnesha
looks good
anonymous
  • anonymous
Are you sure everything looks right?
Nnesha
  • Nnesha
i know what u r talking about when you put sin(27 degree) into the calculator you will get .45399 so you should round it .45399=.4540
Nnesha
  • Nnesha
|dw:1440791354591:dw|
Nnesha
  • Nnesha
now divide 34/.4540
anonymous
  • anonymous
Yes, my answer is: 74.889, which will then round to 74.89. Which is B. :)
Nnesha
  • Nnesha
yes :=)
anonymous
  • anonymous
Could you possibly help me on another question?
Nnesha
  • Nnesha
i'll try
anonymous
  • anonymous
Okay, would you like it in a different post or here is fine?
Nnesha
  • Nnesha
doesn't matter :=) post that here i'm okay with it
anonymous
  • anonymous
Find the value of the cot 10° using your calculator. Answer choices: A) 0.176 B) 5.671 C) 0.648 D) 1.542
Nnesha
  • Nnesha
okay use calculator then :D
anonymous
  • anonymous
How would I type that in though?
Nnesha
  • Nnesha
what is the reciprocal of cot ?
anonymous
  • anonymous
Hmm, I'm sorry haha, I don't understand this question at all, it wasn't in the lesson I got my notes from..
Nnesha
  • Nnesha
alright then write these down in ur notebook \[\large\rm sin \theta = \frac{ 1 }{ \csc \theta }~~~\cos \theta=\frac{ 1 }{ \sec \theta}~~~\tan \theta=\frac{ 1 }{ \cot \theta }=\frac{ \sin \theta}{ \cos \theta}\]
Nnesha
  • Nnesha
tan =1/cot or you can say it's equal to sin/cos
Nnesha
  • Nnesha
csc , sec and tan are reciprocal of sin ,cos and cot
Nnesha
  • Nnesha
csc = 1/sin sin =1/csc
Nnesha
  • Nnesha
so if tan = sin /cos cot = ?
anonymous
  • anonymous
1?
Nnesha
  • Nnesha
what is the reciprocal of sin/cos ?
anonymous
  • anonymous
tan.
Nnesha
  • Nnesha
okay so cot =1/tan \[\huge\rm tan = \frac{ 1 }{ \cot }~~and~~ \cot =\frac{ 1 }{ \tan}\]
Nnesha
  • Nnesha
if tan equal sin/cos then replace tan with sin /cos
Nnesha
  • Nnesha
okay so cot =1/tan \[\huge\rm \cot =\frac{ 1 }{ \color{red}{\tan}}\]\[\cot = \frac{ 1 }{ \color{Red}{\frac{ \sin }{ \cos }} }\]
anonymous
  • anonymous
Okay, so you're basically switching them around? With the originally formula.
Nnesha
  • Nnesha
just remember tan =sin/cos
Nnesha
  • Nnesha
yes right
Nnesha
  • Nnesha
now cot = ??
Nnesha
  • Nnesha
\[\huge\rm \frac{ 1 }{ \frac{ \sin }{ \cos } } = ?\]we can change division to multiplication right
anonymous
  • anonymous
I'm so confused, I'm understanding pieces but then I'm not.. As I said before, I've never seen this type of question or even demonstration in a lesson I've had.
Nnesha
  • Nnesha
okay let's change that to simple algebra \[\huge\rm \frac{ 1 }{ \frac{ a }{ b } }\] how would you simplify it ?
anonymous
  • anonymous
Multiplying?
Nnesha
  • Nnesha
multiply the `numerator` by the `reciprocal` of the bottom fraction \[\huge\rm \frac{ 1 }{ \frac{ a }{ b } }=1 \times \frac{b}{a}\]
anonymous
  • anonymous
Why did you change b as the numerator and a as the denominator?
Nnesha
  • Nnesha
ohh so you don't know the definition of reciprocal reciprocal means `flip` the fraction reciprocal of 2/3 is 3/2
Nnesha
  • Nnesha
so reciprocal of a/b would be b/a so to change division to multiplication you should always multiply the numerator with the `reciprocal` of the bottom
anonymous
  • anonymous
Oh okay, I understand.
Nnesha
  • Nnesha
so what is reciprocal of sin/cos ?
anonymous
  • anonymous
Well, you said reciprocal means to flip the fraction, so would it be cos/sin? Or would it be csc/sec?
Nnesha
  • Nnesha
no just cos /sin
Nnesha
  • Nnesha
tan = sin/cos and cot is `reciprocal` of tan then cot would be cos/sin
Nnesha
  • Nnesha
\[\huge\rm cot \theta= \frac{ \cot \theta }{ \sin \theta }\]\[\huge\rm cot(10^o)= \frac{ \cos (10)^o }{ \sin(10^o) }\]
anonymous
  • anonymous
Okay, I understand what's going on now. So you'd fill in the 10 degrees with the cot function?
Nnesha
  • Nnesha
another example \[\huge\rm \cot (a) =\frac{ \cos(a) }{ \sin(a)}\]
Nnesha
  • Nnesha
yes you have to find cot (10 deg) which is not in the calcualtor so you should put cos(10)/sin(10)
Nnesha
  • Nnesha
cot(10) is same as cos(10)/(sin 10)
anonymous
  • anonymous
It'll give me 5.671. Which is B. I'll have to review those functions more because it's still confusing but I can understand what you're saying. I'll just need to do some more practice.
Nnesha
  • Nnesha
yes practice ,practice and practice you will become trig expert!
Nnesha
  • Nnesha
let me know if you din't understand anything on this post i'll try my best to explain! :=) good luck!

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