In △JKL, solve for x. Answer Choices: A) 66.73 B) 74.89 C) 15.44 D) 38.16

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In △JKL, solve for x. Answer Choices: A) 66.73 B) 74.89 C) 15.44 D) 38.16

Mathematics
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1 Attachment
\[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\]
|dw:1440790508463:dw|

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Other answers:

which function you should use to find x ?
The Cos function?
which side is adjacent of 27 degree angle ?
Side KL with the 34 in the middle
hmm that would be the opposite side adjacent side would the touch |dw:1440790695818:dw| the angle now look at 27 degree angle
kl is adjacent of theta it's a opposite side of 27 degree angle not adj
Oh, yes. I forgot about the Theta,
to find length of x you should know one angle and one side so we would use sin function
|dw:1440790850611:dw|
Wait, how'd you get the Adjacent onto the opposite side? Is it being flipped because of the 27 degrees?
different angles different sides
|dw:1440791024957:dw|
JK is n't opposite side of 27 angle
yep right solve for x
Okay, just a second :)
|dw:1440791173523:dw|
Then my answer was: 74.906
looks good
Are you sure everything looks right?
i know what u r talking about when you put sin(27 degree) into the calculator you will get .45399 so you should round it .45399=.4540
|dw:1440791354591:dw|
now divide 34/.4540
Yes, my answer is: 74.889, which will then round to 74.89. Which is B. :)
yes :=)
Could you possibly help me on another question?
i'll try
Okay, would you like it in a different post or here is fine?
doesn't matter :=) post that here i'm okay with it
Find the value of the cot 10° using your calculator. Answer choices: A) 0.176 B) 5.671 C) 0.648 D) 1.542
okay use calculator then :D
How would I type that in though?
what is the reciprocal of cot ?
Hmm, I'm sorry haha, I don't understand this question at all, it wasn't in the lesson I got my notes from..
alright then write these down in ur notebook \[\large\rm sin \theta = \frac{ 1 }{ \csc \theta }~~~\cos \theta=\frac{ 1 }{ \sec \theta}~~~\tan \theta=\frac{ 1 }{ \cot \theta }=\frac{ \sin \theta}{ \cos \theta}\]
tan =1/cot or you can say it's equal to sin/cos
csc , sec and tan are reciprocal of sin ,cos and cot
csc = 1/sin sin =1/csc
so if tan = sin /cos cot = ?
1?
what is the reciprocal of sin/cos ?
tan.
okay so cot =1/tan \[\huge\rm tan = \frac{ 1 }{ \cot }~~and~~ \cot =\frac{ 1 }{ \tan}\]
if tan equal sin/cos then replace tan with sin /cos
okay so cot =1/tan \[\huge\rm \cot =\frac{ 1 }{ \color{red}{\tan}}\]\[\cot = \frac{ 1 }{ \color{Red}{\frac{ \sin }{ \cos }} }\]
Okay, so you're basically switching them around? With the originally formula.
just remember tan =sin/cos
yes right
now cot = ??
\[\huge\rm \frac{ 1 }{ \frac{ \sin }{ \cos } } = ?\]we can change division to multiplication right
I'm so confused, I'm understanding pieces but then I'm not.. As I said before, I've never seen this type of question or even demonstration in a lesson I've had.
okay let's change that to simple algebra \[\huge\rm \frac{ 1 }{ \frac{ a }{ b } }\] how would you simplify it ?
Multiplying?
multiply the `numerator` by the `reciprocal` of the bottom fraction \[\huge\rm \frac{ 1 }{ \frac{ a }{ b } }=1 \times \frac{b}{a}\]
Why did you change b as the numerator and a as the denominator?
ohh so you don't know the definition of reciprocal reciprocal means `flip` the fraction reciprocal of 2/3 is 3/2
so reciprocal of a/b would be b/a so to change division to multiplication you should always multiply the numerator with the `reciprocal` of the bottom
Oh okay, I understand.
so what is reciprocal of sin/cos ?
Well, you said reciprocal means to flip the fraction, so would it be cos/sin? Or would it be csc/sec?
no just cos /sin
tan = sin/cos and cot is `reciprocal` of tan then cot would be cos/sin
\[\huge\rm cot \theta= \frac{ \cot \theta }{ \sin \theta }\]\[\huge\rm cot(10^o)= \frac{ \cos (10)^o }{ \sin(10^o) }\]
Okay, I understand what's going on now. So you'd fill in the 10 degrees with the cot function?
another example \[\huge\rm \cot (a) =\frac{ \cos(a) }{ \sin(a)}\]
yes you have to find cot (10 deg) which is not in the calcualtor so you should put cos(10)/sin(10)
cot(10) is same as cos(10)/(sin 10)
It'll give me 5.671. Which is B. I'll have to review those functions more because it's still confusing but I can understand what you're saying. I'll just need to do some more practice.
yes practice ,practice and practice you will become trig expert!
let me know if you din't understand anything on this post i'll try my best to explain! :=) good luck!

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