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horsegal244

  • one year ago

Below! 8)

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  1. horsegal244
    • one year ago
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  2. horsegal244
    • one year ago
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    @phi

  3. phi
    • one year ago
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    it helps if we divide the shaded area into rectangles and triangles.

  4. horsegal244
    • one year ago
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    ok but i only have 10 mins so can we do this quickly?

  5. horsegal244
    • one year ago
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    @phi !!

  6. horsegal244
    • one year ago
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    @poopsiedoodle

  7. phi
    • one year ago
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    you need to find the lengths of the red lines

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  8. phi
    • one year ago
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    can you find the area of the bottom rectangle, using length*width? then the area of the middle rectangle then the area of the top triangle

  9. horsegal244
    • one year ago
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    10 in 8

  10. horsegal244
    • one year ago
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    16= bottom 10= mid idk=top

  11. phi
    • one year ago
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    the top triangle has "height" 8 ft (whole side) minus 2 +2+1

  12. horsegal244
    • one year ago
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    3?

  13. phi
    • one year ago
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    yes, and width 10

  14. horsegal244
    • one year ago
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    30

  15. phi
    • one year ago
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    it is a triangle 1/2 * base * ht

  16. horsegal244
    • one year ago
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    15

  17. phi
    • one year ago
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    now add them up. that is the area of the shaded region

  18. horsegal244
    • one year ago
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    41

  19. phi
    • one year ago
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    and for the non-shaded area find the area of the "big box" and subtract 41 from it.

  20. horsegal244
    • one year ago
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    its 87 i think..

  21. phi
    • one year ago
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    yes

  22. trwatkins1
    • one year ago
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    phi when your done here can you help me please

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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