Quick question. What's the domain for this?

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- BloomLocke367

Quick question. What's the domain for this?

- schrodinger

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- anonymous

for what?

- BloomLocke367

|dw:1440792391540:dw|
I'm not sure if it's \(-6

- BloomLocke367

I know I didn't include the points, but that's what they are, lol

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## More answers

- BloomLocke367

- freckles

the open circles means the relation doesn't exist there

- freckles

your relation is not defined anywhere else for x=-6 or x=3
so you definitely will not include x=-6 or x=3

- BloomLocke367

So the first inequality was correct?

- freckles

yes you don't want to include x=-6 or x=3
and your second inequality does that
that is what the little horizontal lines under the inequalities mean
less than or equal to

- imqwerty

yea the 1st inequality is correct cause the values -6 and 3 are omitted in the graph :)

- BloomLocke367

Yes, I know that part @freckles. haha

- BloomLocke367

Thanks!

- freckles

oh then I guess I wasn't sure why you were asking why not to include the equality part

- BloomLocke367

Idek why I was uncertain. I think it's because it was a circle and it was on both sides, but I don't know XD thanks thought :)

- freckles

|dw:1440793380136:dw|
if it was this then you say:
\[-6 < x \le 3 \]

- freckles

|dw:1440793415292:dw|
or if it was this then you would say:
\[-6 \le x \le 3 \]

- imqwerty

but hey do we know where is the center of the circle? is it situated at the origin?

- freckles

and the one more possibility just for fun:
|dw:1440793456096:dw|
then you would say:
\[-3 \le x < 6 \]

- BloomLocke367

Yes, I know what the closed and open circles mean lol XD and no, it's not. I just did a quick sketch of a circle. I have it in front of me on an actual graph with points. I understand now. Thanks

- freckles

@imqwerty i think it is not a circle because the midpoint of x=-6 and x=3 is not 0

- freckles

not a circle centered at (0,0)*

- imqwerty

wait sorry

- imqwerty

i asked the most stupid question :'( :P

- imqwerty

damn

- BloomLocke367

it is a circle. the center is at (-1,1). I just didn't draw it that way

- BloomLocke367

Okay, I do have ONE more question on this topic.

- BloomLocke367

Just a clarification, really.

- BloomLocke367

|dw:1440793616192:dw|
those bottom points all have the same y-values, I just didn't bother showing it. XD But one is open and one is closed so would the inequality be the less than or equal to symbol...since it still touches that point in other areas?

- BloomLocke367

well, not really that point, but that y-value

- freckles

so are you looking at range then

- BloomLocke367

yes

- freckles

|dw:1440793821415:dw|
well a is included

- freckles

because that one dot is filled at y=a

- freckles

so the range would be [a,b]

- freckles

or equivalently an inequality form
a<=y<=b

- BloomLocke367

So I was right. Thanks! I just wanted to make sure I wasn't wrong. xp

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