BloomLocke367
  • BloomLocke367
Quick question. What's the domain for this?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
for what?
BloomLocke367
  • BloomLocke367
|dw:1440792391540:dw| I'm not sure if it's \(-6
BloomLocke367
  • BloomLocke367
I know I didn't include the points, but that's what they are, lol

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BloomLocke367
  • BloomLocke367
@imqwerty
freckles
  • freckles
the open circles means the relation doesn't exist there
freckles
  • freckles
your relation is not defined anywhere else for x=-6 or x=3 so you definitely will not include x=-6 or x=3
BloomLocke367
  • BloomLocke367
So the first inequality was correct?
freckles
  • freckles
yes you don't want to include x=-6 or x=3 and your second inequality does that that is what the little horizontal lines under the inequalities mean less than or equal to
imqwerty
  • imqwerty
yea the 1st inequality is correct cause the values -6 and 3 are omitted in the graph :)
BloomLocke367
  • BloomLocke367
Yes, I know that part @freckles. haha
BloomLocke367
  • BloomLocke367
Thanks!
freckles
  • freckles
oh then I guess I wasn't sure why you were asking why not to include the equality part
BloomLocke367
  • BloomLocke367
Idek why I was uncertain. I think it's because it was a circle and it was on both sides, but I don't know XD thanks thought :)
freckles
  • freckles
|dw:1440793380136:dw| if it was this then you say: \[-6 < x \le 3 \]
freckles
  • freckles
|dw:1440793415292:dw| or if it was this then you would say: \[-6 \le x \le 3 \]
imqwerty
  • imqwerty
but hey do we know where is the center of the circle? is it situated at the origin?
freckles
  • freckles
and the one more possibility just for fun: |dw:1440793456096:dw| then you would say: \[-3 \le x < 6 \]
BloomLocke367
  • BloomLocke367
Yes, I know what the closed and open circles mean lol XD and no, it's not. I just did a quick sketch of a circle. I have it in front of me on an actual graph with points. I understand now. Thanks
freckles
  • freckles
@imqwerty i think it is not a circle because the midpoint of x=-6 and x=3 is not 0
freckles
  • freckles
not a circle centered at (0,0)*
imqwerty
  • imqwerty
wait sorry
imqwerty
  • imqwerty
i asked the most stupid question :'( :P
imqwerty
  • imqwerty
damn
BloomLocke367
  • BloomLocke367
it is a circle. the center is at (-1,1). I just didn't draw it that way
BloomLocke367
  • BloomLocke367
Okay, I do have ONE more question on this topic.
BloomLocke367
  • BloomLocke367
Just a clarification, really.
BloomLocke367
  • BloomLocke367
|dw:1440793616192:dw| those bottom points all have the same y-values, I just didn't bother showing it. XD But one is open and one is closed so would the inequality be the less than or equal to symbol...since it still touches that point in other areas?
BloomLocke367
  • BloomLocke367
well, not really that point, but that y-value
freckles
  • freckles
so are you looking at range then
BloomLocke367
  • BloomLocke367
yes
freckles
  • freckles
|dw:1440793821415:dw| well a is included
freckles
  • freckles
because that one dot is filled at y=a
freckles
  • freckles
so the range would be [a,b]
freckles
  • freckles
or equivalently an inequality form a<=y<=b
BloomLocke367
  • BloomLocke367
So I was right. Thanks! I just wanted to make sure I wasn't wrong. xp

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