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anonymous

  • one year ago

What is the mean absolute deviation for 9, 7, 6, 8, 7, and 5? 1 2 6 7

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  1. anonymous
    • one year ago
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    @Nnesha

  2. anonymous
    • one year ago
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    @tkhunny hello :D

  3. tkhunny
    • one year ago
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    Have you considered calculating the mean and the subsequent absolute deviations?

  4. anonymous
    • one year ago
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    Well i came here for help to learn how.. D:

  5. tkhunny
    • one year ago
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    I do not believe you cannot calculate the mean. Go!

  6. anonymous
    • one year ago
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    mean is 7

  7. tkhunny
    • one year ago
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    Perfect. Now, how far away from the mean is each of the values? We want ABSOLUTE deviation, so don't worry about direction. Just how far away from 7 is it?

  8. anonymous
    • one year ago
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    2 1 2 3 4 are the numbers i got if im understanding correctly

  9. tkhunny
    • one year ago
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    I'm not sure how you managed those values. 9 - 7 = 2 ==> 2 7 - 7 = 0 ==> 0 6 - 7 = -1 ==> 1 8 - 7 = 1 ==> 1 7 - 7 = 0 ==> 0 5 - 7 = -2 ==> 2 You should get 2 0 1 1 0 2

  10. anonymous
    • one year ago
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    ok and what do i do with the numbers you gave me?

  11. tkhunny
    • one year ago
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    Are you sure they are correct? What is an "Absolute Deviation"? Think on it and BE SURE!

  12. anonymous
    • one year ago
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    i meant 2 0 1 1 0 2

  13. tkhunny
    • one year ago
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    So did I. Do you believe those values? If you don't believe and aren't sure where they came from, we can't move on.

  14. anonymous
    • one year ago
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    they are correct.

  15. anonymous
    • one year ago
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    i looked at the math its correct.

  16. tkhunny
    • one year ago
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    Calculate the mean of those values.

  17. anonymous
    • one year ago
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    1

  18. tkhunny
    • one year ago
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    Review: 1) Calculate the mean of the data. 2) Calculate the deviation from the mean for each datum. This is the "Deviation". 3) Use "Absolute Value" on each deviation to create the "Absolute Deviation". 4) Find he mean of the values from #3 to create the "Mean Absolute Deviation". You should see how the very name of the calculation suggests how to calculate it. Good work.

  19. anonymous
    • one year ago
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    Thank you sensei! xD

  20. tkhunny
    • one year ago
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    I hope you have accomplished your stated goal, "Well i came here for help to learn how.. D:". :-)

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