anonymous
  • anonymous
Solve log 2x^2 + 2 = 6. Round to the nearest thousandth if necessary.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
I though i'd reopen a new one. Was afk for a long time
Nnesha
  • Nnesha
so parentheses isn't there ? right ?
Nnesha
  • Nnesha
you can tag me 'n the last post :=)

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anonymous
  • anonymous
nope no parenthesis look just like this \[2x^2 + 2 =6\]
Nnesha
  • Nnesha
alright so you work is correct!
Nnesha
  • Nnesha
ur*
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @lostinprague I subtract 2 from both sides log10 (2x^2) + 2 -2 = 6-2 log10 (2x^2)=4 I then used a = logb (b^a) so... 4= log10 (10^4) log10 (2x^2) = log10 (10^4) then all this other stuff/ not sure I want to type it all out lol \(\color{blue}{\text{End of Quote}}\)
anonymous
  • anonymous
okay so it was 50squareroot 2 or 70.711 then? I think thats what I had down
anonymous
  • anonymous
yeah thats my work
anonymous
  • anonymous
thanks for helping me :)
Nnesha
  • Nnesha
yes right np :=)

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