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anonymous

  • one year ago

Solve log 2x^2 + 2 = 6. Round to the nearest thousandth if necessary.

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  1. anonymous
    • one year ago
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    I though i'd reopen a new one. Was afk for a long time

  2. Nnesha
    • one year ago
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    so parentheses isn't there ? right ?

  3. Nnesha
    • one year ago
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    you can tag me 'n the last post :=)

  4. anonymous
    • one year ago
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    nope no parenthesis look just like this \[2x^2 + 2 =6\]

  5. Nnesha
    • one year ago
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    alright so you work is correct!

  6. Nnesha
    • one year ago
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    ur*

  7. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @lostinprague I subtract 2 from both sides log10 (2x^2) + 2 -2 = 6-2 log10 (2x^2)=4 I then used a = logb (b^a) so... 4= log10 (10^4) log10 (2x^2) = log10 (10^4) then all this other stuff/ not sure I want to type it all out lol \(\color{blue}{\text{End of Quote}}\)

  8. anonymous
    • one year ago
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    okay so it was 50squareroot 2 or 70.711 then? I think thats what I had down

  9. anonymous
    • one year ago
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    yeah thats my work

  10. anonymous
    • one year ago
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    thanks for helping me :)

  11. Nnesha
    • one year ago
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    yes right np :=)

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spraguer (Moderator)
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